Statements M @ D, D δ K, K © R Conclusions I. R $ M II. K δ M III. K $ M

Statements
M @ D ⇒ M ≥ K,
D δ K ⇒ D = K, K © R ⇒ K > R
So, M ≥ K = D > R
Conclusions
I. R $ M ⇒ R < M      (true)
II. K δ M ⇒ K = M      ( may be)
III. K $ M ⇒ K < M      ( may be)
So, from the given statements either II or III and I are true.