Curved surface area = 2?r2
= 2? x 14 x 14 = 2 x (22/7) x 14 x 14
= 2 x 22 x 2 x 14
= 88 x 14
= 1232 sq cm
Volume of small spheres
= Volume of bigger sphere / Number of small spheres = [(4/3)?(4)3] / 64
= [(4/3) x ? x 4 x 4 x 4] / 64
= 4/3 ? cm3
Let radius of small sphere be r
? 4/3?r3 = 4?/3
? r2 = 1 cm
Now, surface area of small sphere = 4?r2 = 4? cm2
Let the diameter's of two sphere are d1 and d2, respectively.
? Ratio of their surface areas = 4?r12/4?r22
= (2r1)2/(2r2)2 = d12/d22
= (d1/d2)2 = (3/5)2 = 9/25 = 9 : 25
Curved surface area of the sphere = 4?r2
or 616 = 4?r2
? ?r2 = 616/4 = 154
? r2 = (154 x 7) / 22 = 49
? r = ?49 = 7 cm
? Volume of the sphere = (4/3)?r3
= (4/3) x (22/7) x 7 x 7 x 7
= 4312 / 3 cm3
Curved surface area of the hemisphere = 2?r2
= 2 x (22/7) x (7/2) x (7/2) = 77 sq
As bowl is to painted inside and outside.
? Total surface to be painted = 77 x 2 = 154 sq cm
? Cost of painting 154 sq cm = (5/10) x 154 = 1/2 x 154 = ? 77
Radius of the sphere = 16/2 = 8 cm
Volume of the sphere = (4/3) x ? x 8 x 8 x 8 cm3
Radius of each lead ball = 2/2 = 1 cm
Volume of each lead ball = Volume of sphere / Volume of lead ball
= (4/3) ? x 1 x 1 x 1 = 4?/3 cm3
? Number of lead balls = [(4/3) x ? x 8 x 8 x 8 x 3] / [4 ?]
= 8 x 8 x 8 = 512
Given,
Diameter = 2 cm
? r = 1 cm
Now, Total surface area of hemisphere = 3?r2
and curved surface area = 2?r2
Required difference = 3?r2 - 2?r2 = ?r2
= ? x 12 = ? sq cm
Let radius of the third sphere be r.
Then, 4/3 ? x (12)3 = 4/3 ? x (6)3 + 4/3? x (8)3 + 4/3 ?r3
? (12)3 = (6)3 + (8)3 + r3
? r3 = 1728 - 216 - 512
? r3 = 1000
? r = 10 cm
According to the formula
Percentage increase in surface area = [ 2x + x2/100]%
= [2 x 3 + (3)2/100]%
= [6 + 0.09]%
= 6.09%
According to the formula,
Percentage decrease in surface area = [2 x (-24) + (-24) x (-24)/100]%
= [-48 + 5.76]% = - 42.24%
Here, n = 100%
According to the formula
Percentage increase in volume = [(1 + n/100)3 - 1] x 100%
= [(1 + 100/100)3 - 1] x 100%
= [8 - 1] x 100% = 700%
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