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- Question
- Ramesh invested an amount that is 10% of ? 10000 at simple interest. After 3 yr, the amount becomes ? 2500. Find out the 4 times of actual interest rate.
Options- A. 5000%
- B. 250%
- C. 200%
- D. 600%
- Correct Answer
- 200%
ExplanationInvestment of Ramesh = 10% of 10000 = ? 1000
After 3 yr = 2500 - 1000 = ? 1500
We know.
SI = (P x R x T)/100
? 1500 = (1000 x R x 3)/100
? R = (1500 x 100) / (1000 x 3) = 50%
? 4 times of 50% = 200% - 1. The simple interest on a sum of money will be ? 200 after 5 yr In the next 5 yr principal is tripled. What will be the total interest at the end of the 10th yr?
Options- A. ? 650
- B. ? 850
- C. ? 800
- D. ? 750 Discuss
- 2. The principle on which a simple interest of ? 55 will be obtained after 9 months at the rate of 3 2/ 3% per annum is
Options- A. 1000
- B. 1500
- C. 2000
- D. 2500 Discuss
- 3. The simple interest on a sum of money is 1 / 16 of the principal and the number of years is equal to the rate per cent annum. Find the rate per cent.
Options- A. 21/2
- B. 31/2 %
- C. 41/2 %
- D. 91/2 % Discuss
- 4. The simple interest of a sum of money is 1/144 of the principal and the number of years is equal to the rate per cent per annum. What will be the rate per cent per annum?
Options- A. 3/5%
- B. 5/6%
- C. 7/6%
- D. 1/6% Discuss
- 5. Rashim lent ? 600 to Geeta for 2 yr and ? 150 to Seeta 4 yr and received altogether ? 80 as simple interest from both. Find the rate of interest.
Options- A. 34/9%
- B. 24/9%
- C. 54/9%
- D. 44/9% Discuss
- 6. What will be the ratio of simple interest earned by certain amount at the same rate of interest for 12 yr and for 18 yr?
Options- A. 2 : 5
- B. 1 : 3
- C. 2 : 3
- D. 3 : 1 Discuss
- 7. A sum of Rs . 2600 is lent out in two part in such a way that the interest on one part at 10% for 5 years is equal to that on another part at 9% for 6 years. The sum lent out at 10% is?
Options- A. Rs. 1150
- B. Rs. 1250
- C. Rs. 1350
- D. Rs. 1450 Discuss
- 8. Simple interest on a certain sum at a certain rate is 9/16 of the sum. If the number representing rate percent and time in years be equal. Then the time is?
Options- A. 51/2years
- B. 61/2years
- C. 61/4years
- D. 71/2years Discuss
- 9. The rate of interest on a sum of money is 4% per annum for the first 2 year, 6% per annum for the next 4 year and 8% per annum for the period beyond 6 years. If the simple interest accrued by the sum for a total period of 9 years is Rs. 1120. What is the sum?
Options- A. Rs. 1500
- B. Rs. 2000
- C. Rs. 2500
- D. Rs. 4000 Discuss
- 10. If A is the simple interest on B and B is the simple interest on C, the rate % and and the time being the same in both cases, what is the relation between A, B and C?
Options- A. A2 = BC
- B. B2 = AC
- C. C2 = AB
- D. ABC = 1 Discuss
Simple Interest problems
Search Results
Correct Answer: ? 800
Explanation:
According to the question,
SI for 5 yr = ? 200
? Total SI for 10 yr = 200 + 600 = ? 800
When principal is trebled, then SI for 5 yr will also be treble and hence
SI for next 5 yr will be ? (200 x 3) i.e., ? 600.
Correct Answer: 2000
Explanation:
Let. principal = P
Given, SI = 55, Time T = 9 months = 9/12 yr,
Rate R = 32/3% = 11/3 %
? SI = (P x R x T) / 100
? P = (100 x SI) / (R x T)
? (55 x 100) / [(11 x 9) / (3 x 12)] = 2000
? Principal (P) = ? 2000
Correct Answer: 21/2
Explanation:
Let principal = P, time = T and rate = T
According to the question,
(P x T x T) / 100 = P/16 [? time and rate are equal]
? T2 = 100/16
or T = 10/4 = 5/2 = 21/2 %
Correct Answer: 5/6%
Explanation:
Let the principal be P.
Then, according to the question,
(P x T x T) / 100 = P/144 [? time and rate are equal]
? T2 = 100/144
? T = 10/12 = 5/6 %
Correct Answer: 44/9%
Explanation:
Given. T1 = 2 yr and T2 = 4 yr,
P1 = 600, P2 = 150.
According to the question,
SI1 + SI2 = 80
[(600 x R x 2)/100] + [(150 x R x 4)/100] = 80
? 120R + 60R = 800
? 180R = 800
? R = 800/180 = 80/18 = 40/9
= 44/9%
Correct Answer: 2 : 3
Explanation:
If the principal = P and interest = R%
Then, required ratio = [(P x R x 12)/100] / [(P x R x 18)/100]
= 12 / 18
= 2/3
= 2 : 3
Correct Answer: Rs. 1350
Explanation:
Let the money at 10% be Rs. P, Then the money at 9% is Rs. (2600 - P )
? (P x 10 x 5)/100 = [(2600 - P ) x 9 x 6]/100
or 104 x P = 2600 x 54
or P = (2600 x 54) / 104 = Rs.1350
Correct Answer: 71/2years
Explanation:
Let principle = P, then SI = (9/16) x P.
Let rate = R% per annum and time = R years
Then, 9/16 P = P x R x R / 100
? R2 = 900/16
? R = 30/4 = 71/2 years
Correct Answer: Rs. 2000
Explanation:
Let sum= Rs. P
Then, [(P x 4 x 2) /100] + [(P x 6 x 4) / 100] + [(P x 8 x 3) /100] = 1120
? 56 x P = 112000
? P = 112000/56 = Rs. 2000
Correct Answer: B2 = AC
Explanation:
? A = (B x R x T) / 100 ....(i)
And B = (C x R x T) / 100 ...(ii)
From Eq. (i) and (ii)
? A/B = B/C
? B2 = AC
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