Volume Box for Aggregates – 35 litre (0.035 m³) measuring box A standard 35 litre measuring box (used for volumetric proportioning of aggregates) should have internal dimensions whose product equals 35,000 cm³. Which set of dimensions below best matches this requirement?

Introduction / Context:
On smaller jobs, aggregates are sometimes measured by volume using boxes of known capacity. Accuracy depends on using a box with correct internal volume and filling method. A 35 litre box corresponds to 0.035 m³ or 35,000 cm³.

Given Data / Assumptions:

• Required volume = 35 litres = 35,000 cm³.
• Dimensions given are internal, in centimetres.
• No allowances are made for wall thickness; only net volume matters.

Concept / Approach:
Compute the product L * B * H for each option and compare with 35,000 cm³. Select the option closest to the target volume. This confirms whether a purported 35 litre box actually provides the intended capacity.

Step-by-Step Solution:
(a) 30 * 25 * 30 = 22,500 cm³ → 22.5 L (too small).(b) 39 * 25 * 32 = 31,200 cm³ → 31.2 L (too small).(c) 27 * 27 * 48 = 34,992 cm³ → ≈ 35.0 L (closest match).(d) 220 * 25 * 40 = 220,000 cm³ → 220 L (way too large).Therefore, option (c) is the correct set.

Verification / Alternative check:
Converting to cubic metres: 34,992 cm³ = 0.034992 m³, which is within rounding of 0.035 m³ used in practice.

Why Other Options Are Wrong:

• (a) and (b) yield significantly smaller volumes than 35 L.
• (d) is vastly larger and not a realistic measuring box.
• “None of these” is invalid because (c) is a close match.

Common Pitfalls:
Relying on nominal box labels without verifying internal dimensions; variations can alter actual proportions and water demand.

Final Answer:
Length 27 cm, breadth 27 cm, height 48 cm