Difficulty: Easy
Correct Answer: At high frequencies, charging and discharging the gate capacitance will draw a heavy current from the power supply and thus increase power dissipation.
Explanation:
Introduction / Context:
CMOS logic exhibits very low static power, but dynamic (switching) power dominates as frequency rises. Understanding the C * V^2 * f relationship is essential for low-power design and for sizing decoupling networks and regulators in fast digital systems.
Given Data / Assumptions:
Concept / Approach:
Each transition moves charge Q = C * V between the rails. The energy drawn per transition is approximately E = C * V^2. With f transitions per second (scaled by toggle probability and activity factor), average dynamic power is P ≈ C * V^2 * f * alpha. Therefore, higher f linearly increases dynamic power for a given voltage and capacitance budget.
Step-by-Step Solution:
Verification / Alternative check:
Measure supply current vs. clock rate on a CMOS device; current rises roughly linearly with frequency for a fixed activity factor.
Why Other Options Are Wrong:
Common Pitfalls:
Ignoring activity factor (alpha) and short-circuit current during transitions, which also contribute but still increase with f.
Final Answer:
At high frequencies, charging and discharging the gate capacitance will draw a heavy current from the power supply and thus increase power dissipation.
Discussion & Comments