Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:Digital clocks increment seconds once every second, then roll over to minutes and hours. In HDL (VHDL/Verilog) implementations, a clean 1 pps tick derived from a crystal time base or external reference is often used to clock the synchronous counters that hold seconds, minutes, and hours.
Given Data / Assumptions:
Concept / Approach:Using a single synchronous clock simplifies timing closure and eliminates ripple delays inherent in asynchronous chains. The 1 pps tick serves as the sole clock, while enable conditions inside each counter determine whether a given stage increments on that tick (for example, minutes increment when seconds = 59 then wraps).
Step-by-Step Solution:
Generate a clean 1 pps from a stable oscillator using a divider.Use the 1 pps as the shared clock for all counters (seconds, minutes, hours).Implement synchronous enable logic to step minutes/hours at the correct rollover events.Maintain synchronous resets for well-defined startup states.Verification / Alternative check:Simulation waveforms show all counters advancing on the same clock edge; synthesis reports confirm a single global clock domain, reducing skew problems compared to ripple chains.
Why Other Options Are Wrong:
Incorrect: Synchronous 1 pps clocking is a standard, robust approach.Only correct if ripple-cascaded / only for minutes: Misunderstands that “synchronous” means shared clock, not asynchronous ripple behavior.Common Pitfalls:Deriving 1 pps with asymmetric duty or jitter; mixing clock domains inadvertently; failing to debounce external references.
Final Answer:Correct
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