Hydrostatics: depth of centre of pressure for a vertical rectangular gate 4 m wide and 3 m high with its top at the free surface (water up to the top) is

Difficulty: Medium

Correct Answer: 2.0 m

Explanation:


Introduction / Context:
The centre of pressure is the point of action of the resultant hydrostatic force on a submerged plane surface. For vertical gates, correctly locating this point is crucial for hinge design, anchor sizing, and stress checks.


Given Data / Assumptions:

  • Vertical rectangular plate: width b = 4 m, height h = 3 m.
  • Top edge at the free surface; hydrostatic pressure due to water only.
  • Uniform gravitational acceleration and density.


Concept / Approach:

The depth to the centroid (centre of area) from the free surface is y_bar = h/2. The centre of pressure depth y_cp for a vertical plane surface with top at the free surface is y_cp = y_bar + (I_G / (A * y_bar)), where I_G is the second moment of area about the horizontal centroidal axis and A is the area.


Step-by-Step Solution:

Compute area: A = b * h = 4 * 3 = 12 m^2.Centroid depth: y_bar = h/2 = 1.5 m.Second moment about centroidal horizontal axis: I_G = (b * h^3)/12 = 4 * 27 / 12 = 9 m^4.Compute the term I_G/(A * y_bar) = 9 / (12 * 1.5) = 9 / 18 = 0.5 m.Therefore y_cp = 1.5 + 0.5 = 2.0 m from the free surface.


Verification / Alternative check:

Centre of pressure should lie below the centroid (because pressure increases with depth). The value 2.0 m > 1.5 m satisfies this physical expectation.


Why Other Options Are Wrong:

(a) and (b) place the resultant above the centroid, impossible here. (d) and (e) are deeper than warranted by the area moment ratio and overestimate lever arms and moments.


Common Pitfalls:

Using I about the free surface instead of about the centroid; forgetting that the top is at the surface, which simplifies the formula.


Final Answer:

2.0 m

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion