Centre of pressure for a vertical plane surface: Select the correct formula for the depth h of the centre of pressure from the free surface (IG = second moment of area about the horizontal centroidal axis, A = area of immersed surface, x = depth of centroid).
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Ah = x + (IG / (A * x))
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Bh = x - (IG / (A * x))
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Ch = (IG / (A * x))
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Dh = (A * x) / IG
Answer
Correct Answer: h = x + (IG / (A * x))
Explanation
Introduction / Context:The centre of pressure is the point of application of the resultant hydrostatic force on a plane surface. For a vertical surface, pressure increases linearly with depth, shifting the resultant below the centroid. The exact depth ensures moment equivalence between the distributed pressure and a single resultant force.
Given Data / Assumptions:
- Vertical plane surface fully or partially submerged.
- Hydrostatic condition (no motion).
- Free surface exposed to uniform atmospheric pressure.
Concept / Approach:Resultant hydrostatic force F = ρ * g * A * x. Taking moments about the free surface and equating to the moment of the resultant at depth h yields h = x + IG / (A * x). Since IG/(A * x) is positive, h > x, meaning the centre of pressure lies below the centroid for a vertical surface.
Step-by-Step Solution:
Compute resultant: F = ρ * g * A * x.Hydrostatic moment: M = ρ * g * IG.Set F * h = ρ * g * IG ⇒ h = IG / (A * x) + x.Verification / Alternative check:For a thin vertical rectangle with centroid at x, the addition IG/(A*x) is nonzero, so h is always below the centroid, matching intuition from the linear pressure distribution.
Why Other Options Are Wrong:
- x − IG/(A * x): Would place h above the centroid, contradicting physics.
- IG/(A * x) alone: Omits the centroidal depth term.
- (A * x)/IG: Inverts the relationship and has wrong dimensions.
Common Pitfalls:Forgetting to include the centroidal term x; confusing IG about the centroid with second moment about the free surface.
Final Answer:h = x + (IG / (A * x))