Compute degree of saturation S: A natural soil has water content w = 15%, specific gravity Gs = 2.50, and void ratio e = 0.5. What is the degree of saturation?
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A50%
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B60%
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C75%
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D80%
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E40%
Answer
Correct Answer: 75%
Explanation
Introduction / Context:
The degree of saturation S quantifies how much of the void space is filled with water. It is a key parameter for evaluating compressibility, permeability, and strength. With water content, specific gravity, and void ratio known, S can be computed from standard mass–volume relationships used in soil mechanics.
Given Data / Assumptions:
- w = 15% = 0.15.
- Gs = 2.50.
- e = 0.5.
- rho_w is taken as 1.0 in consistent units so it cancels in ratios.
Concept / Approach:
The relationship among w, S, e, and Gs is: w = (S * e) / Gs. Rearranging gives S = (w * Gs) / e. This comes from equating the mass of water to the mass of solids times water content and expressing void volume in terms of e.
Step-by-Step Solution:
Write formula: w = (S * e) / Gs.Rearrange: S = (w * Gs) / e.Substitute: S = (0.15 * 2.50) / 0.5 = 0.375 / 0.5 = 0.75.Convert to percent: S = 75%.Verification / Alternative check:
Check bounds: S must lie between 0% and 100%. The computed 75% is physically reasonable for a natural deposit at modest moisture content.
Why Other Options Are Wrong:
- 50% and 60% underestimate S for the given w, e, and Gs.
- 80% is higher than the computed value.
- 40% is far too low.
Common Pitfalls:
- Mistaking porosity n for void ratio e in the formula; the correct relation uses e.
- Forgetting to convert percent water content to a decimal before substitution.
Final Answer:
75%