Dynamic pile formula (Engineering News): A drop hammer weighs 1,800 kg and falls freely through 1.00 m onto a pile. If the penetration under the last blow is 5 mm, estimate the allowable load from the Engineering News formula.
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A100 tonnes
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B50 tonnes
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C20 tonnes
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D10 tonnes
Answer
Correct Answer: 10 tonnes
Explanation
Introduction / Context:Dynamic formulae offer quick estimates of pile capacity from driving data. The classic Engineering News (EN) formula relates hammer energy per blow to allowable load using an empirical set-up term to account for losses and uncertainties, especially for drop hammers.
Given Data / Assumptions:
- Hammer weight W = 1,800 kg ≈ 1.8 tonnes.
- Free fall H = 1.00 m ≈ 3.28 ft.
- Final set s = 5 mm ≈ 0.197 in.
- Drop hammer (use EN constant c = 1 inch in the denominator; W in tons, H in feet, s in inches).
Concept / Approach:Engineering News (imperial form for drop hammers):Q_allow (tons) = (2 * W * H) / (s + 1)where W is in tons, H in feet, s in inches. Convert given metric quantities to these units and substitute.
Step-by-Step Solution:
Convert: W = 1.8 tons (approx), H = 1.00 m = 3.28 ft, s = 5 mm = 0.197 in.Compute numerator: 2 * 1.8 * 3.28 ≈ 11.81.Denominator: s + 1 = 0.197 + 1 = 1.197.Q_allow ≈ 11.81 / 1.197 ≈ 9.86 tons ≈ 10 tonnes (rounded).Verification / Alternative check:Different national adaptations exist (metric forms using kN and mm with constants like 2.5). Using the classic EN (drop hammer) form produces a result near 10 tons, matching the provided options.
Why Other Options Are Wrong:
- 100 or 50 tonnes: Far too large for the given modest hammer and set.
- 20 tonnes: Double the computed value; inconsistent with EN formula.
Common Pitfalls:Mixing units; using the steam/air hammer constant instead of the drop-hammer constant; forgetting that the EN value is an allowable (already conservative) estimate.
Final Answer:10 tonnes