Ohm’s law application — computing current: For a linear resistor, the current through it can be found by dividing the voltage across it by its resistance value. Assess this statement.

Introduction / Context:
Being fluent with Ohm’s law is essential in electronics. The law ties three quantities—voltage, current, and resistance—into a simple relationship that allows any one to be found if the other two are known. This question checks whether the most common rearrangement, I = V / R, is recognized as valid for a linear resistor.

Given Data / Assumptions:

• Ideal linear (ohmic) resistor.
• Steady-state DC or RMS sinusoidal AC conditions.
• No parasitic effects (inductance/capacitance) that would alter the basic relationship.

Concept / Approach:
Ohm’s law in its basic form is V = I * R. Algebraically solving for current gives I = V / R. This holds for DC and for AC when using RMS values for purely resistive circuits. In the presence of reactance (inductors, capacitors), impedance generalizes resistance, but for a plain resistor, the simple division gives the correct current value.

Step-by-Step Solution:

Verification / Alternative check:
Lab measurements of a resistor with a known value confirm linear I–V behavior. Plotting current versus voltage yields a straight line with slope 1/R, matching I = V / R at all tested points within tolerance.

Why Other Options Are Wrong:

• Incorrect: Contradicts the defining relationship for resistors.
• Correct only for AC / only at 25 °C: Ohm’s law applies broadly; temperature changes R slightly but the formula remains valid with the correct R value.

Common Pitfalls:
Mixing peak and RMS values in AC; neglecting tolerance and temperature coefficients when high precision is needed.

Final Answer:
Correct.