C#.NET — What will the corrected program print? (Assume the intended method name is fun1, not funl.) namespace CuriousTabConsoleApplication { class SampleProgram { static void Main(string[] args) { int i = 5; int j; fun1(ref i); fun2(out j); Console.WriteLine(i + ", " + j); } static void fun1(ref int x) { x = x * x; } static void fun2(out int x) { x = 6; x = x * x; } } }
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A5, 6
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B5, 36
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C25, 36
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D25, 0
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E5, 0
Answer
Correct Answer: 25, 36
Explanation
Introduction / Context:The original snippet contains a likely typographical error: fun1 is called but funl is defined. Assuming the intended name is fun1, this question examines ref and out semantics and arithmetic updates.
Given Data / Assumptions:
- i starts at 5 and is passed by ref to fun1.
- j is declared unassigned and passed as out to fun2.
- fun1 squares its argument; fun2 sets x = 6 and then squares it.
Concept / Approach:ref passes an existing variable for in-place modification. out requires assignment inside the method before use. After both calls, Console.WriteLine prints the final values.
Step-by-Step Solution:
fun1(ref i): i becomes 5 * 5 = 25.fun2(out j): j is set to 6, then j becomes 6 * 6 = 36.WriteLine prints "25, 36".Verification / Alternative check:Trace variable states after each call or run an equivalent small program.
Why Other Options Are Wrong:
- 5, 6 / 5, 36 / 25, 0 / 5, 0: Each misses one of the squaring operations or misapplies ref/out behavior.
Common Pitfalls:Overlooking the typo and concluding a compile error; the conceptual goal is to assess ref/out effects.
Final Answer:25, 36