In C++ (old-style headers shown), analyze operator overloading, reference binding, and assignment through a reference. What will the following program print? #include class CuriousTab { int x, y; public: CuriousTab(int xx = 0, int yy = 0) { x = xx; y = yy; } void Display() { cout << x << " " << y; } CuriousTab operator +(CuriousTab z) { CuriousTab objTemp; objTemp.x = x + z.x; objTemp.y = y + z.y; return objTemp; } }; int main() { CuriousTab objCuriousTab1(90, 80); CuriousTab objCuriousTab2(10, 20); CuriousTab objSum; CuriousTab &objRef = objSum; objRef = objCuriousTab1 + objCuriousTab2; objRef.Display(); return 0; }

Introduction / Context: This problem checks C++ operator overloading for user-defined types, reference binding to an lvalue object, and calling a member function through a reference after assignment. The code uses an overloaded operator+ that returns a new temporary object whose x and y are element-wise sums.

Given Data / Assumptions:

• CuriousTab stores two ints x and y.
• operator+ forms a temporary with (x + z.x, y + z.y).
• objRef is a reference bound to objSum, so assignments through objRef modify objSum.
• Initial values: objCuriousTab1 = (90, 80), objCuriousTab2 = (10, 20).

Concept / Approach: Compute the sum via the overloaded operator, assign the resulting temporary to objRef (alias of objSum), and then display the stored pair. No dynamic memory or undefined behavior is present; the code is well-formed with old iostream headers.

Step-by-Step Solution:

Verification / Alternative check: If Display were called on objSum directly, it would print the same, proving objRef truly aliases objSum.

Why Other Options Are Wrong:

• Runtime/compile errors: None are present here.
• "9 4": Not related to the arithmetic performed.

Common Pitfalls: Confusing reference binding with copying; here objRef and objSum are the same object. Also, operator+ returns a temporary which is then assigned, not a reference to a local.

Final Answer: The program will print the output 100 100.