In C++ (passing references to a constructor), determine the program's output. The constructor takes two int& parameters and prints the stored values. #include<iostream.h> class CuriousTab { int x, y; public: CuriousTab(int &xx, int &yy) { x = xx; y = yy; Display(); } void Display() { cout << x << " " << y; } }; int main() { int x1 = 10; int &p = x1; int y1 = 20; int &q = y1; CuriousTab objCuriousTab(p, q); return 0; }

Introduction / Context:
This checks basic reference passing into a constructor and immediate printing via a member function. The references are bound to existing lvalues and then copied into data members.

Given Data / Assumptions:

• p binds to x1 (10), q binds to y1 (20).
• Constructor copies values into x and y, then Display() prints them.

Concept / Approach:
Since the parameters are references, they safely bind to the provided lvalues. Inside the constructor, assignments copy those values into the object. Display then prints the pair.

Step-by-Step Solution:

Verification / Alternative check:
If p or q were changed after construction, the object would not reflect changes because x and y store copies, not references.

Why Other Options Are Wrong:
No compile error or garbage printing occurs; addresses are not printed since the stream inserts ints.

Common Pitfalls:
Confusing reference parameters with reference data members; here only parameters are references.

Final Answer:
The program will print the output 10 20.