C++ pointer-based “copy constructor” overload: what will this program print when constructing from a heap object pointer? #include<iostream.h> class CuriousTab{ int x, y; public: CuriousTab(){ x = 0; y = 0; } CuriousTab(int xx, int yy){ x = xx; y = yy; } CuriousTab(CuriousTab objB){ x = objB->x; y = objB->y; } // nonstandard pointer-taking ctor void Display(){ cout << x << " " << y; } }; int main(){ CuriousTab objCuriousTab( new CuriousTab(20, 40) ); objCuriousTab.Display(); }

Introduction / Context:
Here, instead of a standard copy constructor (CuriousTab(const CuriousTab&)), there is a custom constructor taking a pointer. Passing new CuriousTab(20,40) binds to that pointer-taking overload.

Given Data / Assumptions:

• CuriousTab(CuriousTab objB) copies x and y from objB.
• Display() prints x and y.
• Memory leak of the heap object is irrelevant to the printed output but exists.

Concept / Approach:
Resolve overloads: constructing with a pointer selects the pointer-taking constructor, which dereferences fields and copies values.

Step-by-Step Solution:
1) new CuriousTab(20,40) creates a heap object with x=20, y=40.2) That pointer is passed to CuriousTab(CuriousTab), which assigns x=objB->x and y=objB->y.3) Display() prints 20 40.

Verification / Alternative check:
Replace the pointer-ctor with a reference copy-ctor and pass by value to observe identical printed values but without the leak.

Why Other Options Are Wrong:
Default constructor is not selected; there is no compile-time error since overload resolution succeeds; values are not garbage due to definite assignments.

Common Pitfalls:
Thinking this uses a copy constructor; it does not. Also forgetting to delete the heap object (memory leak).

Final Answer:
The program will print the output 20 40 .