In C++, a constructor taking int& parameters increments the arguments: what is printed?\n\n#include <iostream.h>\nclass CuriousTabTest {\npublic:\n CuriousTabTest(int &x, int &y) { x++; y++; }\n};\nint main() {\n int a = 10, b = 20;\n CuriousTabTest objBT(a, b);\n cout << a << " " << b;\n return 0;\n}\n

Introduction / Context:
This question checks understanding of references passed to a constructor and side effects on the original variables a and b when they are modified by reference within the constructor body.

Given Data / Assumptions:

• Constructor parameters are int& (lvalue references).
• Inside the constructor: x++ and y++.
• a = 10 and b = 20 before construction.

Concept / Approach:
When int& parameters are used, the constructor receives aliases to a and b. Any modification (like ++) directly changes the original variables. Therefore, after construction, a == 11 and b == 21, and cout prints those updated values.

Step-by-Step Solution:

Verification / Alternative check:
Changing the constructor to take values (int x, int y) would not change a and b; the program would then print 10 20. References are the key to mutation here.

Why Other Options Are Wrong:

• 10 20: would be correct only if parameters were passed by value.
• Garbage Garbage: no uninitialized use occurs.
• Compile time error: code is valid for classic iostream.h.

Common Pitfalls:
Confusing pass-by-value with pass-by-reference; expecting constructor parameters to be copies by default.

Final Answer:
11 21