Difficulty: Easy
Correct Answer: 1
Explanation:
Introduction / Context:Specific heat capacity is frequently cited in both SI and English units. Converting correctly between 1 kcal/(kg·°C) and BTU/(lb·°F) prevents significant energy-balance errors in heat-transfer and process calculations.
Given Data / Assumptions:
Concept / Approach:Convert the compound unit stepwise: multiply by the energy conversion, divide by the mass conversion, and divide by the temperature-interval conversion. Algebraically, value in BTU/(lb·°F) = 1 * (3.96832 BTU/kcal) * (1 kg / 2.20462 lb) * (1 °C / 1.8 °F). The mass and temperature conversions together cancel the numerical advantage of the energy conversion, yielding very nearly 1.
Step-by-Step Solution:
Start: 1 kcal/(kg·°C).Apply energy conversion: 1 × 3.96832 → 3.96832 BTU/(kg·°C).Convert mass: 3.96832 / 2.20462 → ≈ 1.800 BTU/(lb·°C).Convert temperature interval: 1.800 / 1.8 → ≈ 1.00 BTU/(lb·°F).Verification / Alternative check:Recognize that the “specific heat of water” near room temperature is ≈ 1 kcal/(kg·°C) and ≈ 1 BTU/(lb·°F); the two definitions were historically aligned to make conversions convenient.
Why Other Options Are Wrong:
Common Pitfalls:Forgetting that degrees Celsius and Fahrenheit use different interval sizes; always include the factor of 1.8 when converting per-degree quantities.
Final Answer:1
Discussion & Comments