Difficulty: Easy
Correct Answer: both (b) and (c)
Explanation:
Introduction / Context:Adding a non-volatile solute to a solvent alters phase-change temperatures in ways that depend only on the number of solute particles (colligative properties). This principle underpins antifreeze formulations, de-icing salts, and boiling point adjustments in cooking and industrial processes.
Given Data / Assumptions:
Concept / Approach:Raoult’s law predicts a lowering of the solvent’s vapor pressure when a non-volatile solute is present. Consequently, a higher temperature is required to reach the external pressure for boiling (boiling-point elevation). Conversely, the presence of solute lowers the chemical potential of the liquid relative to the solid, requiring a lower temperature to achieve phase equilibrium (freezing-point depression). The magnitudes follow ΔT_b = K_b m i and ΔT_f = K_f m i, proportional to molality m and the van ’t Hoff factor i.
Step-by-Step Solution:
Apply Raoult’s law: P_solvent over solution < P_solvent (pure) at same T.Boiling point: need higher T to reach external pressure → boiling-point elevation.Freezing point: solution has lower chemical potential; equilibrium with solid occurs at lower T → freezing-point depression.Therefore, the correct combined statement is “increase in boiling point” and “decrease in freezing point.”Verification / Alternative check:Empirical constants K_b and K_f tabulated for solvents (e.g., water) predict linear changes with molality, confirming the qualitative outcomes.
Why Other Options Are Wrong:
Common Pitfalls:Ignoring electrolyte dissociation (van ’t Hoff factor) which amplifies the effects; confusing non-volatile with volatile solutes where additional vapor-phase behavior applies.
Final Answer:both (b) and (c)
Discussion & Comments