Enriching air with pure oxygen: What is the required mole ratio of air to added O2 to obtain an oxygen-enriched stream containing 50% O2 by volume (assume dry air contains 21% O2)?

Introduction / Context:Air enrichment by blending pure oxygen with air is used in combustion intensification and medical or environmental applications. Determining the correct blend ratio is a straightforward material-balance problem using mole fractions (equal to volume fractions for gases at common T and P).

Given Data / Assumptions:

• Dry air contains 21% O2 by volume (mole basis).
• Target mixture contains 50% O2 by volume.
• Pure O2 is blended with air; inert nitrogen comes only from air.

Concept / Approach:Let x = moles of air, y = moles of pure O2 added. Oxygen in the blend = 0.21x + y; total moles = x + y. The design requirement is (0.21x + y)/(x + y) = 0.50. Solve for y/x to get the mixing ratio, then invert to obtain air:oxygen.

Step-by-Step Solution:

Verification / Alternative check:Assume x = 1 mol air, y = 0.58 mol O2. O2 fraction = (0.21 + 0.58)/(1 + 0.58) = 0.79/1.58 ≈ 0.50, confirming the calculation.

Why Other Options Are Wrong:

• 0.58 is the inverse ratio (O2 per air), not air per O2.
• 0.50 and 0.20 are unrelated to the derived ratio.
• 2.50 gives an O2 fraction far from 50%.

Common Pitfalls:Using mass instead of mole/volume fractions for gas blending; forgetting that the inerts (chiefly N2) come only from air and dilute the final O2 fraction.

Final Answer:1.72