Difficulty: Easy
Correct Answer: Wet vapour (low-pressure liquid–vapour mixture)
Explanation:
Introduction / Context:The throttling valve (expansion device) is a key element in a vapor-compression cycle. It produces a large pressure drop with essentially no external work and negligible heat transfer, setting up the low-temperature conditions needed in the evaporator.
Given Data / Assumptions:
Concept / Approach:When a high-pressure liquid flashes across the throttling device to a much lower pressure, part of it vaporizes to satisfy the energy balance at constant enthalpy. The exit therefore is a two-phase mixture at the lower pressure: a wet vapour with low quality (typically 0.1–0.3), ready to absorb heat in the evaporator.
Step-by-Step Solution:
Upstream state: near saturated liquid at condenser pressure.Throttling: h2 ≈ h3, no work, negligible heat exchange, large pressure drop.Downstream state: mixture at evaporator pressure with temperature equal to saturation at that pressure.Conclusion: wet vapour (liquid–vapour mixture) enters the evaporator.Verification / Alternative check:Plot on a pressure–enthalpy diagram; the throttling line is vertical (constant enthalpy) from saturated liquid region into the two-phase dome.
Why Other Options Are Wrong:
Common Pitfalls:Assuming throttling “cools to vapor”; actually it creates a cold mixture, not dry vapor.
Final Answer:Wet vapour (low-pressure liquid–vapour mixture)
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