What would be the compound interest accrued on an amount of ₹ 8400 @ 12.5 p.c.p.a. at the end of 3 years?
Aptitude
Compound Interest
Difficulty: Medium
Choose an option
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A₹ 2584.16
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B₹ 3560.16
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C₹ 3820.14
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D₹ 4205.62
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ENone of these
Answer
Correct Answer: ₹ 3560.16
Explanation
### Concept & Fractional Rates
When the rate of interest is a standard fraction (like $12.5\% = \frac{1}{8}$), converting the percentage to a fraction simplifies the calculation of the amount significantly.
$$ A = P(1 + \frac{1}{8})^n $$
### Step-by-Step Solution
* **Given:** Principal ($P$) = ₹ 8400, Rate ($R$) = $12.5\% = \frac{1}{8}$, Time ($n$) = 3 years.
* **Step 1:** Set up the amount equation using the fraction.
$A = 8400 \times (1 + \frac{1}{8})^3$
$A = 8400 \times (\frac{9}{8})^3$
* **Step 2:** Expand the calculation.
$A = 8400 \times \frac{729}{512}$
* **Step 3:** Simplify the multiplication.
$A = \frac{8400}{512} \times 729 = 16.40625 \times 729$
$A = 11960.15625$
* **Step 4:** Calculate Compound Interest.
$CI = A - P = 11960.15625 - 8400 = 3560.15625$
* **Step 5:** Round to two decimal places (standard for currency).
$CI \approx 3560.16$
### Exam Strategy & Shortcut
Use digital sum or approximation if the options are far apart. However, since the options are precise and contain decimals, exact calculation using the fractional equivalent $\frac{1}{8} \rightarrow \frac{9}{8}$ is the most structured approach.
### Common Pitfall
Trying to calculate $(1.125)^3$ via standard decimal multiplication takes far too much time and increases the risk of arithmetic errors compared to using fractions.
### Final Answer
Therefore, the correct answer is **₹ 3560.16**.