Code-operator logic – under the mapping x→+, <→−, +→÷, >→×, −→=, ÷→>, =→<, determine which statement is true.

Introduction / Context:This is a symbol-decoding problem where each comparison or arithmetic operator represents a different real operator. We must decode each expression fully and then evaluate using standard precedence rules, keeping comparisons in their correct roles after mapping.

Given Data / Assumptions:

• Mapping: x→+, <→−, +→÷, >→×, −→=, ÷→>, =→<.
• Exactly one of the four options becomes a true statement under this mapping.

Concept / Approach:Translate symbols before computing. After translation, handle × and ÷ first, then + and −, and finally evaluate comparisons. Chain comparisons should be read in order; once decoded, you typically compare left block to right block with the mapped comparator.

Step-by-Step Solution:

Verification / Alternative check:Briefly check the others after mapping: they resolve to false inequalities (e.g., yielding 14 = 0 or 1 > 3, which are false).

Why Other Options Are Wrong:

Common Pitfalls:Partially decoding or forgetting to enforce correct operator precedence after translation.

Final Answer:5 > 2 + 2 = 10 < 4 x 8