Difficulty: Medium
Correct Answer: btbtb
Explanation:
Introduction / Context:
This question belongs to the “letter and symbol series” family. The goal is to infer a deterministic rule from the visible letters and fill each gap group with exactly one character, moving left-to-right. The completed string must be consistent with the smallest, repeatable pattern that explains all fixed letters.
Given Data / Assumptions:
Concept / Approach:
Prefer the simplest repeatable alternation interleaving the fixed anchors “b”, “y”, “…by…”, “…b…yt”. We look for a cadence that: (1) reproduces “b…y…by…b…yt” with regular spacing, and (2) does so using a single-cycle or short-cycle interleaving across all five fills.
Step-by-Step Solution:
1) Label five blanks as X1..X5.2) Try a minimal alternation that keeps “b” and “y” in phase: insert “t” after each “y” anchor and “b” after segments preceding “y”.3) Candidate sequence “btbtb” yields: btytb by t b b yt, which aligns a regular pattern of “t/b” fills around the fixed ‘b…y…by…b…yt’ scaffolding.4) No conflicts with fixed letters; cadence remains consistent across all five placements.
Verification / Alternative check:
Alternative strings (e.g., “bgtbt”, “atbbt”, “cbbte”) either introduce extraneous letters that fail to form a single repeating alternation or break adjacency regularity near “…by…” and “…yt”.
Why Other Options Are Wrong:
Common Pitfalls:
Counting underscores as total missing characters instead of gap groups; assuming multi-letter inserts per group; ignoring left-to-right mapping of options.
Final Answer:
btbtb
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