Complete the letter series by filling the blanks left-to-right. Rule: Each "_" is one letter; use lowercase as shown. Series: g _ _ g _ _ gh _ g _ i
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AhhiiHH
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Bjkljkl
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ChijklI
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Dhih iih
Answer
Correct Answer: hihiih
Explanation
Introduction / Context:This is a structured series completion task. We must fill six gap groups with one letter each, using the smallest deterministic rule that explains all fixed letters “g”, “h”, “i” placements.
Given Data / Assumptions:
- Stem groups: g _ _ | g _ _ | gh _ | g _ | i
- All blanks accept lowercase letters.
- There are 6 fills (X1..X6) read left-to-right.
Concept / Approach:The visible scaffold “g … g … gh … g … i” suggests an interleave of the natural run g→h→i, where “h” clusters around each “g” and “i” marks the terminal escalation. A minimal rule: after each “g”, place “h” first; where a pair of blanks follow, alternate “h/i” to maintain growth towards the final “i”.
Step-by-Step Solution:1) After the first “g__”, insert “h i”.2) After the second “g__”, again insert “h i”.3) In “gh_”, the only next minimal step is “i”.4) In “g_”, use “i” to maintain the rising approach to the terminal “i”.
Verification / Alternative check:The fills “h i | h i | i | i” concatenate to “hihiih”, satisfying a consistent rising pattern and aligning the final anchor “... g _ i”.
Why Other Options Are Wrong:
- jkljkl: Introduces letters not supported by the scaffold and overshoots the g–h–i band.
- hhiiHH: Mixed casing and non-minimal repetition; violates lowercase constraint.
- hijklI: Unequal step sizes and casing issues; not a smallest consistent rule.
Common Pitfalls:Confusing total underscores with number of gap groups; ignoring case uniformity; forcing long cycles when a short interleave suffices.
Final Answer:hihiih