CMOS fan-out behavior: Evaluate — “The fan-out of CMOS gates is frequency dependent.”

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
CMOS inputs are high-impedance and draw negligible DC current, which suggests very high DC fan-out. However, at practical operating frequencies, input capacitance and trace capacitance demand dynamic charging/discharging current. This behavior makes effective fan-out frequency dependent.


Given Data / Assumptions:

  • CMOS inputs present capacitance (Cin), not significant DC current.
  • Output stage has finite drive (Ron, Iout).
  • Rise/fall times degrade as capacitive load increases with more loads or higher frequency.


Concept / Approach:
As frequency increases, the product of load capacitance and edge rate requirements forces more current, slowing transitions and possibly violating timing/noise margins. Therefore, the number of inputs that a CMOS output can reliably drive at a given frequency (i.e., effective fan-out) decreases as frequency rises.


Step-by-Step Solution:

Model each additional gate input as added capacitance.Compute dynamic current using I = C * dV/dt and power using P = C * V^2 * f.Observe that higher f or larger total C reduces timing margin, limiting practical fan-out.


Verification / Alternative check:
Vendor datasheets specify maximum capacitive loads for given rise/fall times and recommended loading guidelines versus clock frequency.


Why Other Options Are Wrong:

  • Incorrect / frequency-limited statements: The dependence exists across a wide frequency range; it is not restricted to a narrow band.


Common Pitfalls:
Equating DC fan-out (near infinite) with practical AC fan-out; ignoring trace capacitance and routing topology; overlooking that multiple receivers may switch simultaneously.


Final Answer:
Correct

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