Difficulty: Easy
Correct Answer: Two Fab fragments and one Fc fragment
Explanation:
Introduction / Context:
IgG structure determines how antibodies bind antigen and recruit effector functions. Proteolytic cleavage experiments (papain versus pepsin) are classic tools to map domains and understand function.
Given Data / Assumptions:
Concept / Approach:
Papain cleaves IgG above the hinge, yielding two monovalent Fab fragments (each with one antigen-binding site) and one Fc fragment (crystallizable fragment mediating effector functions like complement and Fc receptor binding). In contrast, pepsin cuts below the hinge, producing F(ab')2.
Step-by-Step Solution:
Recall papain action → cleavage above hinge.
Products → Fab + Fab + Fc.
Choose the option explicitly naming these three fragments.
Confirm that other options describe different outcomes (e.g., pepsin makes F(ab')2).
Verification / Alternative check:
Fab retains antigen-binding without effector function; Fc retains constant-region functions without antigen binding.
Why Other Options Are Wrong:
Heavy-light dimers not standard nomenclature; random oligopeptides imply nonspecific digestion; F(ab')2 is pepsin product, not papain.
Common Pitfalls:
Confusing papain with pepsin; mixing up Fab (monovalent) versus F(ab')2 (bivalent).
Final Answer:
Two Fab fragments and one Fc fragment.
Discussion & Comments