Immunoglobulin G (IgG) cleavage: A specific protease (such as papain) splits an IgG molecule into which defined fragments?

Difficulty: Easy

Correct Answer: Two Fab fragments and one Fc fragment

Explanation:


Introduction / Context:
IgG structure determines how antibodies bind antigen and recruit effector functions. Proteolytic cleavage experiments (papain versus pepsin) are classic tools to map domains and understand function.


Given Data / Assumptions:

  • Protease referenced is the classic one used for IgG domain mapping.
  • We consider intact IgG with two antigen-binding arms and one constant Fc region.


Concept / Approach:
Papain cleaves IgG above the hinge, yielding two monovalent Fab fragments (each with one antigen-binding site) and one Fc fragment (crystallizable fragment mediating effector functions like complement and Fc receptor binding). In contrast, pepsin cuts below the hinge, producing F(ab')2.


Step-by-Step Solution:
Recall papain action → cleavage above hinge. Products → Fab + Fab + Fc. Choose the option explicitly naming these three fragments. Confirm that other options describe different outcomes (e.g., pepsin makes F(ab')2).


Verification / Alternative check:
Fab retains antigen-binding without effector function; Fc retains constant-region functions without antigen binding.


Why Other Options Are Wrong:
Heavy-light dimers not standard nomenclature; random oligopeptides imply nonspecific digestion; F(ab')2 is pepsin product, not papain.


Common Pitfalls:
Confusing papain with pepsin; mixing up Fab (monovalent) versus F(ab')2 (bivalent).


Final Answer:
Two Fab fragments and one Fc fragment.

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion