Compare production rates: the yield (filtration rate) of a rapid gravity (rapid sand) filter is typically how many times that of a slow sand filter?
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A10 times
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B15 times
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C20 times
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D30 times
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E35 times
Answer
Correct Answer: 20 times
Explanation
Introduction / Context:Water-treatment plants use either slow sand filters (very low rates, high biological action) or rapid gravity filters (much higher rates with prior coagulation–flocculation). Understanding their typical filtration-rate ratio guides footprint and process selection.
Given Data / Assumptions:
- Slow sand filters: ~2–5 m^3/m^2/day (typical design band).
- Rapid gravity filters: ~80–120 m^3/m^2/day (post-coagulation typical band).
- We are asked for a representative multiple (order-of-magnitude comparison).
Concept / Approach:Taking representative mid-range values (e.g., SSF ≈ 3–4 m^3/m^2/day and RGF ≈ 90–100 m^3/m^2/day) gives a ratio on the order of 20–30. A conservative standard teaching value often cited is about 20 times, which safely represents the magnitude difference for many exam contexts.
Step-by-Step Solution:
Choose SSF typical ≈ 4 m^3/m^2/day; choose RGF typical ≈ 80–100 m^3/m^2/day.Compute ratio ≈ 80/4 to 100/4 = 20–25.Select the closest standard option → 20 times.Verification / Alternative check:Design manuals often present RGF throughput an order of magnitude greater than SSF; the 20× figure sits well within the usual range.
Why Other Options Are Wrong:
- 10× or 15×: Understate the typical difference.
- 30× or 35×: Possible for some plants, but higher than a standard benchmark used in teaching questions.
Common Pitfalls:
- Comparing instantaneous backwash/production cycles rather than net filtration rate.
- Ignoring pretreatment needs that enable RGF's higher rates.
Final Answer:20 times