Fluid Mechanics – Unit of dynamic viscosity (μ) in SI units Select the correct unit.

Difficulty: Easy

Correct Answer: N·s/m²

Explanation:


Introduction / Context:
Dynamic viscosity (μ) quantifies a fluid’s internal resistance to shear. Correct unit recognition is essential for dimensional checks in Navier–Stokes equations, pipe-flow calculations, and lubrication analyses.


Given Data / Assumptions:

  • SI base units are used.
  • Shear stress τ relates to velocity gradient du/dy via τ = μ * (du/dy).
  • Force unit N, length m, time s, mass kg.


Concept / Approach:

From τ = μ * (du/dy), the unit of τ is N/m² (Pa), and du/dy has units s^-1. Hence μ must have units (N/m²) / (s^-1) = N·s/m² = Pa·s. This is the SI unit of dynamic viscosity. Kinematic viscosity ν equals μ/ρ and has units m²/s, distinct from μ.


Step-by-Step Solution:

Start with τ units: N/m².Velocity gradient units: s^-1.Compute μ units: (N/m²)/(s^-1) = N·s/m² = Pa·s.Alternative mass–length–time form: 1 Pa·s = 1 kg/(m·s).


Verification / Alternative check:

Common reference values: water at 20 °C has μ ≈ 1.0 × 10^-3 Pa·s = 1.0 × 10^-3 N·s/m², which is consistent with the derived unit.


Why Other Options Are Wrong:

m²/s is kinematic viscosity; Pa·s/m² introduces an extra per-area term; kg·s²/m² does not correspond to viscosity; N/m² is pressure (stress), not viscosity.


Common Pitfalls:

Confusing μ (dynamic) with ν (kinematic), or mixing SI and CGS units (e.g., poise, centipoise) without proper conversion (1 Pa·s = 10 P = 1000 cP).


Final Answer:

N·s/m²

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