In a plate bearing test, the modulus of subgrade reaction (k) is taken from the load–deflection curve at a standard settlement. Which settlement value (in centimetres) should be used for computing k?

Difficulty: Easy

Correct Answer: 0.125 cm

Explanation:


Introduction / Context:
The modulus of subgrade reaction, k, is a key input for Westergaard plate theory and rigid pavement design. In practice, k is derived from the load–deflection curve of a plate load test at a standard, small deflection so that the response approximates the linear range and represents near-surface stiffness relevant to slabs-on-grade.


Given Data / Assumptions:

  • Field plate load test provides pressure vs. settlement (load–deflection curve).
  • We must select a standard settlement to compute k = pressure / settlement.
  • Rigid pavement design practices typically reference a small elastic deflection.


Concept / Approach:
To allow comparison across sites and tests, standards adopt a reference settlement of 1.25 mm, which equals 0.125 cm. Using this point, the secant stiffness to the origin approximates the subgrade spring constant per unit area. Larger settlements would capture nonlinear or bearing failure effects, not the desired near-elastic response for slab design.


Step-by-Step Solution:

Read the load–deflection curve from the plate test.Locate settlement = 1.25 mm = 0.125 cm.Compute k = q / s at this point (units consistent, e.g., kN/m^3).


Verification / Alternative check:

Back-calculate slab corners/edges deflection using computed k and compare with observed slab behavior for reasonableness.


Why Other Options Are Wrong:

0.175–0.375 cm: larger settlements enter nonlinear ranges and vary with plate size and soil yielding.0.250 cm: too large for the standard definition of k used in rigid pavement design.


Common Pitfalls:

Mixing units (mm vs cm) when computing k; not correcting for plate diameter when correlating to larger slabs.


Final Answer:

0.125 cm

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