Difficulty: Medium
Correct Answer: 0.247 m3
Explanation:
Introduction / Context:
Estimating mortar for plaster involves converting the specified thickness and area into a wet volume, then applying a dry-volume allowance to account for bulking, voids, and handling losses. The cement portion is then extracted from the mix proportion (1 : 6 means 1 part cement to 6 parts sand by volume).
Given Data / Assumptions:
Concept / Approach:
Wet mortar volume = Area × Thickness. Dry volume = wet volume × factor (≈ 1.4 for plastering to include bulking and normal wastage). Cement quantity (loose volume) = (1 / total parts) × dry volume. This method aligns with standard building estimation procedures used in practice and textbooks.
Step-by-Step Solution:
1) Wet volume V_wet = A * t = 100 * 0.012 = 1.20 m^3.2) Dry volume V_dry ≈ 1.4 * V_wet = 1.4 * 1.20 = 1.68 m^3.3) Cement fraction = 1 / (1 + 6) = 1 / 7.4) Cement quantity = V_dry / 7 = 1.68 / 7 ≈ 0.24 m^3 ≈ 0.247 m^3 (rounded to listed option).
Verification / Alternative check:
Using a slightly different factor (e.g., 1.33) plus a small percentage for waste/unevenness leads to a similar cement volume near 0.24–0.25 m^3, consistent with the selected option.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
0.247 m3.
Discussion & Comments