Difficulty: Easy
Correct Answer: to limit the current and protect LED against reverse breakdown voltage.
Explanation:
Introduction / Context:LEDs are current-driven devices with a relatively fixed forward drop over a small current range. Practical LED circuits therefore include a series resistor to set current and a protective diode across the LED (usually antiparallel) to guard against reverse voltage during polarity reversals or inductive transients.
Given Data / Assumptions:
Concept / Approach:The LED must be protected from excessive forward current and from reverse breakdown. The resistor limits forward current: I ≈ (Vs − Vf)/R. The protection diode D provides a safe reverse path with low drop, clamping the reverse voltage across the LED to approximately a diode drop, thereby preventing reverse breakdown of the LED junction.
Step-by-Step Solution:
Forward conduction: R sets I_LED to a safe value by Ohm’s law.Reverse polarity or transient: D conducts first, keeping Vreverse across LED ≈ 0.7–1 V rather than several volts.Therefore, R limits current; D protects against reverse breakdown.Verification / Alternative check:
Check LED datasheet: maximum reverse voltage ratings are low; external diode is recommended in AC drive or inductive environments.Why Other Options Are Wrong:
R does not “limit voltage” directly; it is a current-limiting element.D does not protect primarily against forward “over-current”; that is handled by R.“None” and “boost current” options contradict safe design practice.Common Pitfalls:
Omitting the antiparallel diode when driving LEDs from AC or when inductive kick can occur.Final Answer:
to limit the current and protect LED against reverse breakdown voltage.
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