Assertion–Reason: (A) The conductivity of a p-type semiconductor is higher than that of an intrinsic semiconductor. (R) Adding donor impurities creates extra energy levels just below the conduction band.

Electronics and Communication Engineering Electronic Devices and Circuits Difficulty: Medium
Choose an option
  • A
    Both A and R are true and R is correct explanation of A
  • B
    Both A and R are true but R is not a correct explanation of A
  • C
    A is true but R is false
  • D
    A is false but R is true
  • E
    Both A and R are false

Answer

Correct Answer: A is true but R is false

Explanation

Introduction / Context:Assertion–Reason questions evaluate not only factual correctness but also causal linkage. Here we compare conductivity of p-type versus intrinsic material and examine whether the stated reason logically supports the assertion.

Given Data / Assumptions:

  • Intrinsic semiconductor: n = p = ni; conductivity σi = q ni (μn + μp).
  • p-type semiconductor: majority holes with p ≫ n; conductivity σp ≈ q p μp with p set by acceptor doping.
  • Donor impurities (n-type) introduce energy levels near the conduction band; acceptor impurities (p-type) introduce levels near the valence band.

Concept / Approach:The assertion states p-type conductivity exceeds intrinsic conductivity—usually true, because doping greatly increases majority carrier concentration compared to ni at room temperature. The reason, however, mentions donor impurities (n-type mechanism) rather than acceptors, so it does not explain the improved conductivity of a p-type semiconductor. Thus A is true, R is false in this context.

Step-by-Step Solution:

Assess A: Doping (acceptors) raises hole concentration well above ni → σ increases → A is true.Assess R: Donor levels below conduction band correspond to n-type doping, irrelevant to p-type improvement → R is false as an explanation for A.Therefore, correct choice: A true, R false.

Verification / Alternative check:

If R had referred to acceptor levels near the valence band (promoting holes), it could have explained A. Since it does not, the pairing fails.

Why Other Options Are Wrong:

(a) Incorrect because R does not support A.(b) R is not even true in the p-type context used to explain A.(d) A is not false; p-type typically has higher σ than intrinsic.

Common Pitfalls:

Overlooking the specific impurity type (donor vs acceptor) in reason statements.

Final Answer:

A is true but R is false
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