Question 1

Chain-growth products: chain-growth (addition) polymerisation adds monomers to active chain ends and requires initiators. Which of the following is a product of chain-growth polymerisation?

Accepted Answer

Introduction / Context: Polymerisation route dictates molecular weight build-up and typical structures. Chain-growth (addition) polymerisation proceeds via radicals, ions, or coordination sites adding unsaturated monomers. Recognising which commercial polymers arise from addition vs. condensation pathways is a frequent test of fundamentals. Given Data / Assumptions: Vinyl monomers (like tetrafluoroethylene) form addition polymers. Condensation polymers (nylons, PET, Bakelite) form via step-growth with small-molecule elimination or ring opening. Concept / Approach: PTFE (Teflon) forms by chain-growth addition of tetrafluoroethylene. Nylon-66 and PET are condensation polymers (step-growth) formed from bifunctional monomers eliminating water or methanol; Bakelite is a step-growth phenol–formaldehyde network. Therefore, among the options, PTFE is the clear example of a chain-growth product. Step-by-Step Solution: Classify each listed polymer by mechanism.Recognise PTFE as an addition polymer of TFE.Select “Teflon (PTFE).”Rule out condensation products (nylon-66, PET, Bakelite, polycarbonate). Verification / Alternative check: Mechanistic overviews in polymer texts place vinyl polymers (PE, PP, PVC, PTFE, PS) in the chain-growth category. Why Other Options Are Wrong: Nylon-66/PET/Bakelite/polycarbonate: canonical step-growth systems. Common Pitfalls: Misclassifying ring-opening (e.g., caprolactam to nylon-6) as chain-growth; although it proceeds by chains, it is a step-growth condensation process at the functional group level. Final Answer: Teflon (PTFE)

Question 2

Safety glass laminates: the interlayer that holds broken glass fragments in place during an impact, reducing injury risk, is primarily which polymer?

Accepted Answer

Introduction / Context: Laminated safety glass used in automotive windshields and architectural glazing comprises glass–polymer–glass sandwiches. The interlayer must adhere strongly to glass, absorb impact energy, and hold shards together upon breakage. The industry-standard interlayer is polyvinyl butyral (PVB). Given Data / Assumptions: Target properties: adhesion to glass, toughness, optical clarity, and durability. Processing requires thermoplastic film lamination under heat and pressure. Concept / Approach: PVB, derived from acetalisation of polyvinyl alcohol with butyraldehyde, offers excellent adhesion to glass (especially with appropriate plasticisation and moisture control), high impact resistance, and optical transparency. While other interlayers exist (e.g., EVA, ionoplasts) for specialty glazing, the classic and most widely taught material for safety glass is PVB. Step-by-Step Solution: Connect performance needs (adhesion, toughness, clarity) to interlayer chemistry.Recall PVB as the conventional automotive windshield interlayer.Select “Polyvinyl butyral (PVB).”Rule out PVOH (water-sensitive), generic “acetale,” PVC (clarity and plasticiser issues) for this mainstream application. Verification / Alternative check: Automotive and building codes, as well as supplier literature, consistently specify PVB for laminated safety glazing, with standardized thicknesses (e.g., 0.38 mm, 0.76 mm). Why Other Options Are Wrong: PVOH: hydrophilic; poor durability as a neat interlayer. Polyvinyl acetale (generic): vague; in practice, the butyral acetal (PVB) is used. PVC: plasticiser migration and optics limit use as a safety interlayer. EVA: used in some specialty/photovoltaic laminates but not the canonical answer. Common Pitfalls: Confusing generic “acetals” with the specific butyral derivative proven in safety glass. Final Answer: Polyvinyl butyral (PVB)

Question 3

Styrene–butadiene rubber (SBR): identify the application from the list below for which SBR is never used in standard practice.

Accepted Answer

Introduction / Context: SBR is a general-purpose synthetic rubber valued for abrasion resistance and cost effectiveness. It is ubiquitous in passenger car tyres, footwear, mats, and coated fabrics. However, the extreme demands of aircraft tyres—very high load, speed, temperature rise, and cyclic stress—necessitate specialized rubber formulations dominated by natural rubber (NR) or advanced blends, not conventional SBR as the primary elastomer. Given Data / Assumptions: Aircraft tyres experience severe heat build-up and require exceptional fatigue/crack growth resistance. NR has superior strain-induced crystallisation and tear resistance vs. SBR. SBR is common in many general-duty applications but not in heavy-duty aircraft tyre treads. Concept / Approach: NR’s unique strain-crystallisation provides outstanding cut/tear resistance and resilience, making it the material of choice for aircraft tyre carcasses and treads. SBR lacks comparable fatigue performance under aircraft duty cycles. Hence, “front-wheel tyres of aeroplanes” (representing heavy-duty aircraft tyres) is outside SBR’s typical use envelope. In contrast, SBR latexes and solids are widely used in coated fabrics, shoe soles, gaskets, and vibration-damping parts where performance demands are compatible. Step-by-Step Solution: Assess service severity for each application.Match elastomer capabilities: NR for aircraft; SBR for general-duty goods.Identify the out-of-scope use as heavy-duty aircraft tyres.Select “Front-wheel tyres of aeroplanes (heavy-duty aircraft tyres).” Verification / Alternative check: Tire engineering references specify NR-rich compounds for aircraft tyre treads and carcasses due to heat build-up, load, and safety margins. Why Other Options Are Wrong: Coated fabrics/gaskets/soles/damping pads: all established SBR applications. Common Pitfalls: Assuming automotive tyre practice (SBR blends) directly transfers to the extreme aircraft service environment. Final Answer: Front-wheel tyres of aeroplanes (heavy-duty aircraft tyres)

Question 4

In polymer science, which of the following materials is generally not drawn into fibre form for textile or technical filaments (while the others commonly are)?

Accepted Answer

Introduction / Context: Drawing is the process of orienting polymer chains by stretching a partially solidified filament to improve strength, modulus, and dimensional stability. Most fibre-forming polymers must be linear or lightly branched, with adequate molecular weight and chain flexibility so that they can be melt- or solution-spun and then drawn. This question compares several common polymer families and asks which one is generally not used for fibre drawing. Given Data / Assumptions: Polyamide (nylon), saturated polyester (PET), and polyacrylonitrile (PAN) are classical fibre-forming polymers. Unsaturated polyesters are typically crosslinked thermosetting resins used with fillers/fibres (e.g., glass) to make composites. Drawing requires extensibility and chain mobility prior to final orientation and crystallization; extensive crosslinking prevents this. Concept / Approach: Fibre formation normally uses thermoplastic, linear polymers that can be extruded as filaments and subsequently drawn to align chains. Unsaturated polyester resins are designed to cure into a network (crosslinked) structure through styrenic or similar reactive diluents. After curing, they cannot be softened or stretched to produce oriented fibres. By contrast, nylon, PET, and PAN are archetypal fibre polymers used in apparel, tire cord, and carbon-fibre precursors respectively. Step-by-Step Solution: Identify which listed polymers are linear thermoplastics suitable for fibre spinning.Recognize that unsaturated polyesters cure to a crosslinked network (thermoset).Conclude that unsaturated polyesters are generally not drawn into fibres. Verification / Alternative check: Industrial practice uses PET, nylon, and PAN for fibres at massive scale. Unsaturated polyesters are used as matrices in fibre-reinforced plastics, not as the fibre itself. Why Other Options Are Wrong: Polyamide: classic fibre polymer.Saturated polyester (PET): classic fibre polymer (terylene/dacron).Polyacrylonitrile: key precursor for high-performance carbon fibres.Cellulose acetate: used for cigarette filters and specialty fibres. Common Pitfalls: Confusing “polyester” generally with “unsaturated polyesters”; PET (a saturated polyester) is fibre-forming, whereas unsaturated polyesters are thermoset matrices. Final Answer: Unsaturated polyesters (thermoset resins)

Question 5

Polycondensation (step-growth) polymerisation: which statement correctly describes a material or outcome commonly produced by this mechanism?

Accepted Answer

Introduction / Context: Polymerisation mechanisms are broadly divided into step-growth (polycondensation) and chain-growth (addition). Understanding which polymers derive from which mechanism is fundamental for predicting properties, processing routes, and cure behaviour. This item asks for a true statement about polycondensation outcomes. Given Data / Assumptions: Epoxy resins (e.g., based on bisphenol-A and epichlorohydrin) are produced via step-growth reactions, often with small-molecule byproducts in intermediate steps. Step-growth can form linear or network (crosslinked) structures depending on monomer functionality (difunctional vs. multifunctional). Catalysts or initiators may or may not be required, depending on the specific system. Concept / Approach: In step-growth polymerisation, any two molecular species can react at any time, and high molecular weight emerges only at very high conversion. Epoxy systems are classic step-growth thermosets because multifunctional epoxide and hardener molecules react to build a network during cure. Conversely, claims that step-growth cannot make linear polymers or makes only thermoplastics are false; polyesters and polyamides (linear thermoplastics) are produced by step-growth when difunctional monomers are used. Step-by-Step Solution: List polymers known from step-growth: polyesters, polyamides, phenolics, epoxies.Identify which options align with this list.Select the statement that matches—epoxy polymers are produced by polycondensation (step-growth). Verification / Alternative check: Textbook reaction schemes for epoxy resin production and cure show stepwise glycidyl ether formation and subsequent network formation with hardeners (amines, anhydrides). Why Other Options Are Wrong: “Does not produce linear polymers”: wrong; linear PET and nylons are step-growth.“Produces only thermoplastic”: wrong; many step-growth systems are thermosets.“Never requires catalyst”: incorrect generalization; catalysts are common in condensations.“Always monodisperse”: step-growth typically gives broad distributions unless carefully engineered. Common Pitfalls: Equating “condensation” exclusively with loss of small molecules; some step-growth systems proceed without byproduct. Final Answer: It produces epoxy polymers (epoxy resins).

Question 6

Step-growth polymerisation produces which of the following well-known polymers by a condensation route?

Accepted Answer

Introduction / Context: Polymer synthesis routes strongly influence structure and properties. Step-growth (condensation) polymerisation typically reacts difunctional monomers to form high molecular weight only at high conversion, often producing small-molecule byproducts such as water or methanol. Identifying which commercial polymer arises from step-growth is a frequent exam task. Given Data / Assumptions: Terylene (PET) results from the reaction of terephthalic acid (or its dimethyl ester) with ethylene glycol. Polybutadiene, PVC, PP, and PS are formed predominantly via chain-growth free-radical, coordination, or anionic mechanisms. Concept / Approach: In step-growth, difunctional monomers (e.g., diacids and diols) polymerise to form linear chains. PET is the archetypal saturated polyester produced by this method and widely used for fibres (dacron/terylene), films, and bottles. The other listed polymers are addition polymers assembled by successive propagation of unsaturated monomer units, not by condensation of bifunctional monomers. Step-by-Step Solution: Compare each option’s known synthesis route.Identify PET as the step-growth polyester.Select “Terylene (PET).” Verification / Alternative check: Standard polymer chemistry texts map PET to step-growth; commodity polyolefins and vinyls derive from chain-growth mechanisms. Why Other Options Are Wrong: Polybutadiene: chain-growth (diene polymerisation).PVC / PP / PS: classic chain-growth vinyl/olefin systems. Common Pitfalls: Confusing “polyester” as a broad class; only saturated polyesters like PET for fibres are step-growth, whereas “unsaturated polyesters” are thermoset resins used in composites. Final Answer: Terylene (PET, a saturated polyester)

Question 7

Which polymer is most commonly used to manufacture refrigerator components (liners, trays) and small electronic housings such as radio or transistor parts?

Accepted Answer

Introduction / Context: Selection of plastics for appliance components balances stiffness, processability, surface finish, and cost. Refrigerator liners, trays, and many consumer electronics housings historically use polystyrene (including high-impact polystyrene, HIPS) because it offers good rigidity, ease of thermoforming/injection molding, and acceptable aesthetics. Given Data / Assumptions: Refrigerator components often require thermoformability, dimensional stability, and food-contact compliance. Transistor or small electronic housings require moldability and surface finish. We consider widely used commodity solutions rather than specialty engineering upgrades. Concept / Approach: Polystyrene’s glassy nature at room temperature yields stiffness and dimensional stability, while its melt flow suits complex molds and thermoformed shapes. HIPS adds rubber impact modifiers to improve toughness. Alternatives exist (e.g., ABS or PP in some modern designs), but polystyrene remains a canonical answer for legacy exam questions about refrigerator liners and small electronic casings. Step-by-Step Solution: Evaluate needs: easy forming, adequate rigidity, low cost.Match to polymer properties: PS/HIPS fits well.Select polystyrene as the best-known material for this application. Verification / Alternative check: Industrial practice and product datasheets cite HIPS for refrigerator liners and PS or ABS for small appliance housings; exam conventions typically list polystyrene. Why Other Options Are Wrong: Polypropylene: good for hinges and containers but can suffer from stiffness/finish limits in this traditional context.Unsaturated polyester: thermoset matrix used with fibres, not typical for liners.Polyurethane: commonly used as insulation foam in refrigerators, not for liners or housings.Polycarbonate: excellent but costlier and over-specified for many such parts. Common Pitfalls: Confusing PU foam (insulation) with liner material; liners are commonly PS/HIPS. Final Answer: Polystyrene (PS, including HIPS grades)

Question 8

In the nomenclature nylon-6, what does the number “6” specifically denote in this polyamide system?

Accepted Answer

Introduction / Context: Nylon nomenclature reflects the number of carbon atoms derived from monomers. For homopolyamide nylon-6, the monomer is caprolactam, a cyclic lactam with six carbon atoms. Understanding this convention helps decode structures and relate them to properties such as melting point and moisture uptake. Given Data / Assumptions: Nylon-6 is formed by ring-opening polymerisation of caprolactam. Caprolactam contains a six-carbon backbone contributing to the repeating amide unit. Numbering conventions: nylon-6,6 uses two numbers for diamine and diacid carbon counts; nylon-6 uses a single number from a single monomer. Concept / Approach: For nylons: Nylon-6,6: hexamethylene diamine (6 carbons) + adipic acid (6 carbons) → “6,6.” Nylon-6: caprolactam (6 carbons) → “6.” Thus, the “6” represents the number of carbon atoms in the lactam monomer that becomes part of the polyamide backbone after ring opening and polymerisation. Step-by-Step Solution: Identify nylon-6 monomer: caprolactam.Count carbons in caprolactam: six.Conclude that “6” denotes the carbon count in the monomer, carried into the repeating unit. Verification / Alternative check: Textbook schematics show ring-opening of caprolactam to yield –NH–(CH2)5–CO– repeating units, confirming the six-carbon segment. Why Other Options Are Wrong: Total chain carbons: variable with chain length; not fixed by the name.Nitrogen or hydrogen counts: not part of the nylon numbering convention.Repeating unit per nanometer: unrelated to naming. Common Pitfalls: Confusing nylon-6 with nylon-6,6; the latter uses two monomer carbon counts (6 and 6). Final Answer: Carbon atoms in the monomer ring (caprolactam)

Question 9

Which listed polymer exhibits the weakest intermolecular forces (and hence lowest room-temperature cohesive strength) compared to the others?

Accepted Answer

Introduction / Context: Intermolecular forces such as hydrogen bonding, dipole interactions, and van der Waals forces determine the mechanical strength and thermal properties of polymers. Elastomers like polyisoprene rely on light crosslinking for elasticity and typically have weaker intermolecular attractions between chains compared to polar or crosslinked polymers. Given Data / Assumptions: Nylon-66 has strong hydrogen bonding between amide groups → higher cohesive strength. Bakelite is a crosslinked thermoset → rigid network with strong covalent crosslinks. Polystyrene is a glassy polymer with rigid phenyl groups, offering significant stiffness at room temperature. Polyisoprene in the uncrosslinked or lightly crosslinked state displays low secondary bonding between chains. Concept / Approach: Weak secondary forces translate to lower modulus and lower tensile strength unless reinforced or crosslinked. Polyisoprene’s hydrocarbon backbone and lack of strong polar functionalities make it comparatively weak in intermolecular attractions, enabling rubber-like extensibility but lower unfilled strength. Step-by-Step Solution: Survey each polymer’s bonding and morphology.Identify the one lacking strong polar groups or network crosslinks.Select polyisoprene as having the weakest intermolecular forces among the list. Verification / Alternative check: Material property tables show high hydrogen-bonded strength for nylons and network rigidity for Bakelite; PS is stiff and glassy; unfilled elastomers are comparatively soft. Why Other Options Are Wrong: Nylon-66: strong H-bonding raises cohesion.Bakelite: crosslinked network is very rigid.Polystyrene: glassy with relatively high modulus at room temperature.Polycarbonate: tough engineering plastic with strong intermolecular interactions. Common Pitfalls: Equating elasticity with strength; elastomers stretch easily but do not necessarily have high cohesive strength without fillers/crosslinks. Final Answer: Polyisoprene (natural rubber type)

Question 10

Typical coil/particle size of polymer molecules: choose the most appropriate order-of-magnitude size range (in metres) often cited for macromolecular dimensions in bulk/solution states.

Accepted Answer

Introduction / Context: Polymer “size” depends on context: contour length of a chain, radius of gyration of a coil in solution, or effective hydrodynamic diameter in a dispersion. In many textbook MCQs, an order-of-magnitude estimate is requested to develop intuition for macromolecular dimensions as they relate to colloidal scales and processing behavior. Given Data / Assumptions: We target an order-of-magnitude range for common coil/aggregate scales, not atomic bond lengths. Polymer coils and aggregates can span submicron to micron scales, especially in concentrated solutions, gels, or latexes. The question adopts conventional exam ranges rather than precise values for any specific polymer/solvent pair. Concept / Approach: Molecular dimensions at the scale of individual chains in good solvents can be tens of nanometres, but practical measurements in processing (e.g., latex particles, micelles, or coil aggregates) frequently land in the 10^-7 to 10^-4 m window (0.1 micrometre to 100 micrometres) depending on aggregation and measurement technique. Therefore, among the provided discrete bands, 10^-4 to 10^-7 m is the best conventional pick for polymer-related “particle/coil” scales highlighted in many exam syllabi. Step-by-Step Solution: Review each range vs. colloidal/micron scales.Eliminate ranges that are too macroscopic (10^-1 to 10^-2 m) or too atomic (10^-10 m).Select 10^-4 to 10^-7 m as a representative, syllabus-aligned range. Verification / Alternative check: Light scattering and microscopy studies often report coil radii and aggregate sizes in the submicron-to-micron region, consistent with the chosen band. Why Other Options Are Wrong: 10^-2 to 10^-5 m: includes centimetre scales; too large for molecular/coil dimensions.10^-1 to 10^-2 m: macroscopic.10^-8 to 10^-10 m: mostly atomic/nanoscale limits; too small for many practical coil/aggregate measures.10^-6 to 10^-9 m overlaps a portion but is narrower than the typical exam band presented. Common Pitfalls: Confusing single-chain radius of gyration with latex particle diameters; context matters. Final Answer: 10^-4 to 10^-7 m

Question 11

Gutta-percha rubber: which statement correctly characterises this material relative to natural rubber?

Accepted Answer

Introduction / Context: Natural rubber is predominantly cis-1,4-polyisoprene, conferring high elasticity and tack at room temperature. Gutta-percha is trans-1,4-polyisoprene—a stereochemical isomer with very different properties. Distinguishing these forms illustrates how stereochemistry governs polymer mechanics and thermal behaviour. Given Data / Assumptions: Cis vs. trans configuration along the polyisoprene backbone drastically affects chain packing and crystallinity. Gutta-percha (trans) is more crystalline and harder at room temperature than natural rubber (cis). Thermosets are network polymers; gutta-percha is not crosslinked by default. Concept / Approach: Trans-1,4-polyisoprene chains pack more efficiently, increasing crystallinity and rigidity; therefore, gutta-percha is relatively hard and non-tacky at ambient conditions. This contrasts with cis-1,4-polyisoprene’s elastomeric character. The key relationship is isomerism, not copolymerisation or thermosetting chemistry. Step-by-Step Solution: Identify structural difference: cis vs. trans stereochemistry.Relate trans configuration to increased crystallinity and hardness.Conclude that gutta-percha is an isomer of natural rubber (trans-1,4-polyisoprene). Verification / Alternative check: Physical property tables list higher hardness and lower elasticity for gutta-percha than for natural rubber at room temperature. Why Other Options Are Wrong: Soft and tacky: describes cis rubber, not gutta-percha.Thermosetting resin: incorrect; gutta-percha is a thermoplastic isomer unless vulcanised.Recovered by coagulation of rubber latex: a general statement for natural rubber production; gutta-percha sources and processing differ.Copolymer with styrene: incorrect; gutta-percha is a homopolymer of isoprene. Common Pitfalls: Assuming all “rubbers” are elastomeric at room temperature; stereochemistry can produce hard, crystalline variants. Final Answer: It is an isomer of natural rubber (trans-1,4-polyisoprene).

Question 12

Compared to thermoplastic polymers, thermosetting resins are generally characterised by which of the following behaviours or properties?

Accepted Answer

Introduction / Context: Thermosets and thermoplastics differ structurally: thermosets form three-dimensional crosslinked networks during cure, whereas thermoplastics are linear or lightly branched and soften on heating. Recognising the practical implications of this structural distinction is essential for materials selection. Given Data / Assumptions: Thermosets do not melt upon reheating; they char or degrade. Crosslinking restricts chain mobility, enhancing modulus but reducing ductility and impact strength. Solubility is generally low for crosslinked networks; they may swell but not dissolve. Concept / Approach: Crosslinks lock chains into a rigid network, increasing heat resistance and dimensional stability but making the material more brittle. In contrast, thermoplastics can be remelted and reshaped. Thermosets can be made through step-growth (e.g., epoxies, phenolics, unsaturated polyesters); they are not limited to addition polymerisation. Step-by-Step Solution: Compare structural features: network vs. linear chains.Relate network formation to brittleness and insolubility.Select the statement describing increased brittleness. Verification / Alternative check: Mechanical testing shows higher modulus but lower elongation at break for cured thermosets compared with many thermoplastics. Why Other Options Are Wrong: Soluble in all solvents: networks are typically insoluble.Only by addition polymerisation: epoxies/phenolics are step-growth; the claim is false.Easily reshaped: thermosets cannot be remelted.Always lower Tg: not generally true; some thermosets have very high Tg. Common Pitfalls: Assuming all brittle plastics are thermosets; some thermoplastics are also brittle depending on temperature and formulation. Final Answer: They are more brittle in the cured state.

Question 13

Step-growth (condensation) polymerisation generally involves one reaction type and mechanism; which of the following materials is NOT produced via step-growth routes?

Accepted Answer

Introduction / Context: Industrial polymers are often classified by their synthesis mechanisms. Step-growth systems build molecular weight gradually by reactions of functional groups; chain-growth systems propagate through active centers adding unsaturated monomers. Recognising which materials belong to which category underpins processing and property expectations. Given Data / Assumptions: Phenolic resins, polyesters, polyamides, and epoxies are classic step-growth polymers (often with small-molecule byproducts or stepwise network formation). Polystyrene (including crosslinked grades) is formed by chain-growth free-radical polymerisation of styrene; crosslinking is achieved by comonomers like divinylbenzene. Concept / Approach: Even when polystyrene is crosslinked, the base polymerisation remains a chain-growth addition process initiated by radicals (or anionic routes). By contrast, phenolics, polyesters, and polyamides form by condensations between functional groups (e.g., hydroxyl and carboxyl, amine and acid, phenol and aldehyde). Epoxy networks also form via step-growth reactions between epoxide groups and hardeners. Step-by-Step Solution: List typical step-growth polymers.Identify the outlier: polystyrene (addition polymer).Select crosslinked polystyrene as “not produced by step-growth.” Verification / Alternative check: Mechanistic schemes in polymer texts place vinyl/olefinic systems like styrene firmly in chain-growth categories. Why Other Options Are Wrong: Phenol–formaldehyde, polyesters, polyamides, epoxies: all step-growth systems. Common Pitfalls: Assuming crosslinking implies step-growth; crosslinking can occur in both mechanism families. Final Answer: Crosslinked polystyrene (e.g., with divinylbenzene)

Question 14

Approximate cellulose content in bamboo fibre: choose the closest typical percentage reported for lignocellulosic bamboo.

Accepted Answer

Introduction / Context: Bamboo, like wood, is a lignocellulosic material comprising cellulose, hemicellulose, and lignin. Knowledge of cellulose content is important for pulp and paper, biocomposites, and chemical processing where cellulose provides strength and is the desired fraction for many applications. Given Data / Assumptions: Bamboo cellulose is commonly reported in the rough range of about 40–60 percent depending on species, age, and processing. Hemicelluloses and lignin make up most of the remainder, along with extractives and ash. The question asks for an approximate, typical value among discrete choices. Concept / Approach: Mid-range values near 50 percent are widely cited for bamboo cellulose. Values as low as 10–20 percent are unrealistic for structural lignocellulosics; 85 percent would be closer to purified cellulose or certain highly processed fibres, not raw bamboo fibre content. Therefore, 50 percent is the best representative selection. Step-by-Step Solution: Eliminate choices that are far below typical lignocellulosic cellulose content (10, 20).Eliminate 85, which is characteristic of purified cellulose rather than native bamboo.Choose 50 as a representative midpoint of the common reported range. Verification / Alternative check: Materials data handbooks and pulp studies on bamboo consistently list cellulose near ~50 percent with variability by species. Why Other Options Are Wrong: 10/20: too low for bamboo structure.85: too high for raw bamboo; would imply near-pure cellulose.65: possible in some processed fibres, but higher than typical for native bamboo fibre content. Common Pitfalls: Confusing processed cellulose fibres with native biomass composition. Final Answer: 50

Question 15

Condensation vs. addition polymerisation: which statement correctly distinguishes condensation systems from typical addition systems?

Accepted Answer

Introduction / Context: Polymerisation classifications help predict processing and properties. Condensation (step-growth) polymerisation typically links functional groups like –COOH, –OH, –NH2, or epoxide, sometimes liberating small molecules such as water or methanol. Addition (chain-growth) polymerisation adds unsaturated monomer units to a growing chain via active centers without losing small molecules. Given Data / Assumptions: Difunctional monomers (e.g., diacids, diols, diamines) are common in condensation systems. Some step-growth reactions proceed without byproduct, but many release small molecules. Addition systems typically involve unsaturated monomers (vinyls, dienes, olefins). Concept / Approach: The most reliable general distinction is monomer functionality: condensation polymers are formed when two or more functional groups on different monomers react to form linkages, often producing byproducts. Hence, “monomers generally contain two functional groups” is the correct statement. The other claims are overly absolute or incorrect. Step-by-Step Solution: Identify a generalised property that holds for condensation systems.Verify that difunctionality (or higher) is typical.Select the statement about two functional groups per monomer. Verification / Alternative check: Examples: PET (diacid + diol), nylon (diamine + diacid), phenolics (phenol + formaldehyde) all involve functional-group condensations. Why Other Options Are Wrong: Always unsaturated: false; condensation uses functional groups, not C=C necessarily.No co-product: many condensations release water/methanol, so this is false.Only one monomer: many systems involve two different monomers.Always lower molecular weight: depends on conversion and formulation. Common Pitfalls: Assuming byproduct formation is mandatory; some step-growth systems are “addition–condensation” without small-molecule loss. Final Answer: Condensation monomers generally contain two functional groups each (difunctional).

Question 16

Polytetrafluoroethylene (PTFE) is commercially known by which trade name?

Accepted Answer

Introduction / Context: Common trade names for polymers are widely used in industry and exams. PTFE is a fluoropolymer valued for its exceptionally low friction coefficient, chemical inertness, and high continuous-use temperature, making it a staple in seals, gaskets, and non-stick coatings. Given Data / Assumptions: PTFE = polytetrafluoroethylene. “Teflon” is the well-known trade name historically associated with PTFE products. Other names in options refer to different polymers. Concept / Approach: Mapping common names: Dacron = PET fibre; Bakelite = phenol–formaldehyde thermoset; Celluloid = cellulose nitrate/camphor; Lexan = polycarbonate. Therefore, PTFE corresponds to Teflon. Step-by-Step Solution: Identify polymer: PTFE.Recall trade name: Teflon.Select “Teflon.” Verification / Alternative check: Manufacturer literature and materials handbooks consistently associate PTFE with the Teflon brand. Why Other Options Are Wrong: Dacron: polyester fibre (PET).Bakelite: phenolic thermoset.Celluloid: cellulose nitrate plasticised with camphor.Lexan: polycarbonate. Common Pitfalls: Confusing PTFE with FEP or PFA (other fluoropolymers) that also have Teflon-branded variants; the core association remains PTFE. Final Answer: Teflon

Question 17

The generic chemical class that includes all “nylons” is correctly referred to as which family of polymers?

Accepted Answer

Introduction / Context: Nylons are ubiquitous engineering and fibre polymers. Their key structural feature is the amide linkage (–CONH–) repeated along the chain. A clear understanding of this functional group enables correlation with properties such as hydrogen bonding, crystallinity, and moisture absorption. Given Data / Assumptions: Nylons are formed by condensation of amine- and acid-functional monomers or by ring-opening of lactams. Amide linkages can form strong intermolecular hydrogen bonds. Common nylon types: nylon-6, nylon-6,6, nylon-11, nylon-12, etc. Concept / Approach: The defining feature of “nylon” is the polyamide backbone. Polyolefins (e.g., polyethylene, polypropylene) lack polar groups; polyacrylates have ester groups; polyurethanes have urethane linkages; polysulfones contain sulfone groups. Thus, “polyamides” is the correct family name for nylons. Step-by-Step Solution: Identify the repeating linkage in nylon: amide.Map this to the chemical family: polyamides.Select “Polyamides.” Verification / Alternative check: Standard polymer classifications list nylons under polyamides due to the –CONH– linkage. Why Other Options Are Wrong: Polyolefins: no amide groups.Polyacrylates: ester functionality.Polyurethanes: urethane/urethane carbamate linkages.Polysulfones: sulfone aromatic linkages. Common Pitfalls: Using trade names or numeric designations (6, 6,6, 11) without relating them back to the amide-functional class. Final Answer: Polyamides

Question 18

Thermoplastic materials: which statement correctly describes them among the following choices?

Accepted Answer

Introduction / Context: Thermoplastics are linear or lightly branched polymers that soften on heating and can be reshaped repeatedly within thermal limits. Recognising their behaviour distinguishes them from thermosetting resins, which form permanent crosslinked networks. Given Data / Assumptions: Thermoplastics soften with heat and can be remoulded; they do not irreversibly cure like thermosets. Branching varies by polymer; some are linear (e.g., PET), some branched (e.g., LDPE), some are nearly linear (e.g., HDPE). Solubility is polymer–solvent specific; many thermoplastics are soluble in appropriate solvents. Concept / Approach: Examine each claim for absolute accuracy. “Do not soften” is false; thermoplastics do soften. “Always heavily branched” is false; topology varies. “Insoluble in all solvents” is false; many dissolve in suitable solvents. Hence the only correct choice from the provided options is “None of these.” Step-by-Step Solution: Evaluate thermoplastic behaviour on heating: softening/remelting is expected.Check molecular architecture: not universally heavily branched.Assess solubility: depends on polymer–solvent interactions; not universally insoluble.Conclude that none of the given statements is correct. Verification / Alternative check: Processing of thermoplastics by extrusion, injection moulding, and thermoforming inherently relies on softening/melting upon heating. Why Other Options Are Wrong: (a): Opposite of thermoplastic behaviour.(b): Architecture is polymer-specific.(c): Many thermoplastics are soluble (e.g., PS in aromatic solvents).(e): Describes thermosets, not thermoplastics. Common Pitfalls: Confusing solvent resistance of some engineering thermoplastics with universal insolubility. Final Answer: None of these.

Question 19

Determinants of polymer properties: which collective factors significantly affect bulk properties such as strength, toughness, and thermal response?

Accepted Answer

Introduction / Context: Bulk polymer properties arise from molecular architecture and interactions. Chain length, secondary bonding, and network structure collectively control mechanical, thermal, and rheological behaviour. Recognising the combined influence of these factors is foundational for materials design. Given Data / Assumptions: Higher molecular weight (chain length) generally raises strength and toughness up to a plateau. Intermolecular forces (hydrogen bonding, dipole interactions) strongly affect glass transition and modulus. Branching and crosslinking alter crystallinity, melt viscosity, elasticity, and heat resistance. Concept / Approach: Because all three listed factors are fundamental, the correct choice is the combined option. While tacticity also matters, the question specifically highlights chain length, intermolecular forces, and branching/crosslinking as the principal levers for tuning performance across commodity and engineering polymers. Step-by-Step Solution: Assess effect of chain length → increased entanglement and properties.Assess intermolecular forces → higher Tg and modulus with stronger attractions.Assess branching/crosslinking → modifies crystallinity and thermal stability.Conclude that all these factors together govern properties. Verification / Alternative check: Design of nylon (H-bonded), PET (polar), and PE (varying branching) demonstrates property changes tied to these variables. Why Other Options Are Wrong: Single-factor answers are incomplete.“Only tacticity” excludes equally important determinants listed. Common Pitfalls: Overemphasising one factor (e.g., molecular weight) while ignoring morphology and interactions. Final Answer: All (a), (b), and (c)

Question 20

Vulcanisation of rubber modifies several properties. Which one is NOT increased by vulcanisation?

Accepted Answer

Introduction / Context: Vulcanisation introduces sulfur crosslinks between polyisoprene chains, transforming soft, tacky rubber into an elastic material with improved mechanical and thermal performance. Knowing which properties rise and which fall after vulcanisation is crucial for rubber compounding. Given Data / Assumptions: Crosslinking reduces chain mobility. Elastic recovery, modulus, set resistance, and tear strength typically improve. Plasticity (ease of permanent flow) declines as the network constrains deformation. Concept / Approach: Crosslinks limit viscous flow and permanent deformation, thereby decreasing plasticity. Elasticity and resilience generally increase, while ductility (large plastic deformation) often decreases. Thus, among the listed options, “plasticity” is the property not increased. Step-by-Step Solution: Recall effects of crosslinking on chain mobility.Associate reduced mobility with lower plasticity.Select “Plasticity” as not increased. Verification / Alternative check: Standard rubber testing before and after cure shows higher modulus and lower permanent set, indicating reduced plastic flow. Why Other Options Are Wrong: Elasticity: increases with crosslink density (to a point).Ductility: often decreases; however the question asks which is not increased—plasticity is the clear answer.Tear strength: usually improves with appropriate crosslink density and fillers. Common Pitfalls: Confusing ductility with elasticity; vulcanisation boosts elastic recovery but may reduce ductility. Final Answer: Plasticity

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