Critical speed Nc (rpm) of a ball mill, in terms of mill radius R1 and ball radius R2 (both in metres), is correctly given by which expression?
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ANc = 29.8 / sqrt(R1 + R2)
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BNc = 42.3 / sqrt(R1 - R2)
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CNc = 60 / sqrt(R1 R2)
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DNc = 76.6 / (R1 - R2)
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ENc = 9.81 / (R1 - R2)
Answer
Correct Answer: Nc = 42.3 / sqrt(R1 - R2)
Explanation
Introduction / Context:Critical speed defines the rotational speed at which grinding media just cling to the mill shell. Above this speed, cataracting ceases and grinding action diminishes.
Given Data / Assumptions:
- R1 = mill radius, R2 = ball radius (m).
- g ≈ 9.81 m/s^2; unit conversion to rpm included.
Concept / Approach:At the point of detachment, centripetal acceleration equals gravitational acceleration at the media center: ω^2 (R1 − R2) = g. Hence ω = sqrt(g/(R1 − R2)). Converting to rpm gives Nc = (60 / 2π) * sqrt(g/(R1 − R2)) ≈ 42.3 / sqrt(R1 − R2).
Step-by-Step Solution:Set ω^2 (R1 − R2) = g.Solve ω = sqrt(g/(R1 − R2)).Convert to rpm: Nc = 60 ω / (2π) ≈ 42.3 / sqrt(R1 − R2).
Verification / Alternative check:With D and d as diameters, the familiar form is Nc ≈ 42.3 / sqrt(D − d) (D,d in metres), consistent with the derived expression using radii.
Why Other Options Are Wrong:Other constants or using (R1 + R2) are dimensionally/physically inconsistent.
Common Pitfalls:Forgetting to subtract ball radius; the orbit center is at (R1 − R2).
Final Answer:Nc = 42.3 / sqrt(R1 - R2)