Centroid of a thin hollow cone: For a thin conical surface of height h, the center of gravity measured along the axis above the base lies at what distance?

Difficulty: Easy

Correct Answer: h / 3

Explanation:


Introduction / Context:

Locating centroids is essential for computing moments, stability, and support reactions. A thin hollow cone (a conical shell) has mass concentrated on its surface, not its volume, so its centroid differs from that of a solid cone.


Given Data / Assumptions:

  • Geometric shape: thin conical surface of height h and negligible thickness.
  • Uniform surface density.
  • Axis of symmetry is vertical; base is a circle.


Concept / Approach:

For a solid right circular cone, the centroid lies at h/4 from the base along the axis. For a thin conical shell, the centroid shifts upward because the mass is distributed near the surface farther from the axis compared to volume distribution. The standard result for a thin hollow cone is h/3 above the base along the axis.


Step-by-Step Solution:

Model the shell as a stack of small circular rings along the slant height.Use symmetry to place the centroid on the axis.Integrate ring contributions (proportional to radius) along height to obtain the centroid position y = h / 3 above the base.


Verification / Alternative check:

The value h/3 lies above h/4 (solid cone), consistent with intuition that a shell’s mass is farther from the base centroid than a solid’s mass average.


Why Other Options Are Wrong:

  • h/4 is for a solid cone, not a shell.
  • h/2, 2h/3, 3h/4 place the centroid unrealistically high for this geometry.


Common Pitfalls:

  • Confusing solid and hollow cone centroid formulas.


Final Answer:

h / 3

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