Centroid of a thin hollow cone: For a thin conical surface of height h, the center of gravity measured along the axis above the base lies at what distance?
-
Ah / 3
-
Bh / 4
-
Ch / 2
-
D2h / 3
-
E3h / 4
Answer
Correct Answer: h / 3
Explanation
Introduction / Context:
Locating centroids is essential for computing moments, stability, and support reactions. A thin hollow cone (a conical shell) has mass concentrated on its surface, not its volume, so its centroid differs from that of a solid cone.
Given Data / Assumptions:
- Geometric shape: thin conical surface of height h and negligible thickness.
- Uniform surface density.
- Axis of symmetry is vertical; base is a circle.
Concept / Approach:
For a solid right circular cone, the centroid lies at h/4 from the base along the axis. For a thin conical shell, the centroid shifts upward because the mass is distributed near the surface farther from the axis compared to volume distribution. The standard result for a thin hollow cone is h/3 above the base along the axis.
Step-by-Step Solution:
Model the shell as a stack of small circular rings along the slant height.Use symmetry to place the centroid on the axis.Integrate ring contributions (proportional to radius) along height to obtain the centroid position y = h / 3 above the base.Verification / Alternative check:
The value h/3 lies above h/4 (solid cone), consistent with intuition that a shell’s mass is farther from the base centroid than a solid’s mass average.
Why Other Options Are Wrong:
- h/4 is for a solid cone, not a shell.
- h/2, 2h/3, 3h/4 place the centroid unrealistically high for this geometry.
Common Pitfalls:
- Confusing solid and hollow cone centroid formulas.
Final Answer:
h / 3