Source transformation check: A Thevenin source with VS = 30 V and RS = 6 Ω is transformed to an equivalent Norton current source. What are the Norton parameters (IS in amperes, RN in ohms)?

Introduction / Context:
Source transformation is a core technique for simplifying linear circuits. Any Thevenin source (voltage in series with resistance) can be converted to a Norton source (current in parallel with resistance) and vice versa, without changing the external terminal behavior.

Given Data / Assumptions:

• Thevenin voltage VS = 30 V.
• Thevenin resistance RS = 6 Ω (series).
• All components are linear and time-invariant.

Concept / Approach:

For Thevenin ↔ Norton conversion: IS = VS / RS and RN = RS. The resistance remains the same; only the source form changes between voltage and current.

Step-by-Step Solution:

Verification / Alternative check:

Open-circuit voltage of Norton pair: VOC = IS * RN = 5 * 6 = 30 V, which matches VS. Short-circuit current of Thevenin pair: ISC = VS / RS = 5 A, which matches IS. Equivalence verified.

Why Other Options Are Wrong:

'30 A, 6 Ω' confuses the ratio; '5 A, 30 Ω' changes resistance incorrectly; '30 A, 5 Ω' alters both values; '0.2 A, 6 Ω' is the reciprocal ratio, not applicable here.

Common Pitfalls:

Accidentally inverting VS/RS, or changing the resistance during transformation. Resistance must remain RS in both representations.

Final Answer:

5 A, 6 Ω