In C on a typical 32-bit model (char=1 byte, int=4 bytes, float=4 bytes), what does sizeof report? #include<stdio.h> int main() { char ch = 'A'; printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14f)); return 0; }

Introduction / Context:
This problem checks your knowledge of the sizeof operator in C, particularly how it treats variables, character constants, and floating constants under a typical 32-bit data model where char=1 byte, int=4 bytes, and float=4 bytes.

Given Data / Assumptions:

• char occupies 1 byte.
• int occupies 4 bytes.
• float occupies 4 bytes.
• The code prints three sizeof results in order: sizeof(ch), sizeof('A'), sizeof(3.14f).

Concept / Approach:
sizeof(variable) yields the storage size of that object’s type. In C, a character constant like 'A' has type int (not char), so sizeof('A') equals sizeof(int). A float constant with suffix f has type float.

Step-by-Step Solution:
sizeof(ch) = 1 (because ch is char).sizeof('A') = sizeof(int) = 4 (character constants are of type int).sizeof(3.14f) = sizeof(float) = 4.Printed result: 1, 4, 4.

Verification / Alternative check:
Replace the character constant with a variable: int x = 'A'; sizeof(x) also returns 4 on this model, reinforcing the rule.

Why Other Options Are Wrong:
(a) assumes sizeof('A') is 2, which is nonstandard here. (c) and (d) mismatch the stated data model. (e) incorrectly treats a character constant as a char.

Common Pitfalls:
Believing sizeof('A') equals 1 because it “looks like a char”; forgetting the f suffix forces a float (not double).

Final Answer:
1, 4, 4