Home » C Programming » Functions

What will be the output of the program? #include int i; int fun(); int main() { while(i) { fun(); main(); } printf("Hello\n"); return 0; } int fun() { printf("Hi"); }

Correct Answer: Hello

Explanation:

Step 1: int i; The variable i is declared as an integer type.


Step 1: int fun(); This prototype tells the compiler that the function fun() does not accept any arguments and it returns an integer value.


Step 1: while(i) The value of i is not initialized so this while condition is failed. So, it does not execute the while block.


Step 1: printf("Hello\n"); It prints "Hello".


Hence the output of the program is "Hello".


← Previous Question Next Question→

More Questions from Functions

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion