What will be the output of the program in 16 bit platform (Turbo C under DOS)? #include int main() { int fun(); int i; i = fun(); printf("%d\n", i); return 0; } int fun() { _AX = 1990; }

What will be the output of the program in 16 bit platform (Turbo C under DOS)? #include<stdio.h> int main() { int fun(); int i; i = fun(); printf("%d\n", i); return 0; } int fun() { _AX = 1990; }

Garbage value
0 (Zero)
1990
No output

Correct Answer: 1990

Explanation:

Turbo C (Windows): The return value of the function is taken from the Accumulator _AX=1990.

But it may not work as expected in GCC compiler (Linux).

More Questions from Functions

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What will be the output of the program? #include int check (int, int); int main() { int c; c = check(10, 20); printf("c=%d\n", c); return 0; } int check(int i, int j) { int *p, *q; p=&i; q=&j; i>=45? return(*p): return(*q); }
What will be the output of the program? #include int check(int); int main() { int i=45, c; c = check(i); printf("%d\n", c); return 0; } int check(int ch) { if(ch >= 45) return 100; else return 10; }
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