What will be the output of the program? #include int func1(int); int main() { int k=35; k = func1(k=func1(k=func1(k))); printf("k=%d\n", k); return 0; } int func1(int k) { k++; return k; }

Step 1: int k=35; The variable k is declared as an integer type and initialized to 35.

Step 2: k = func1(k=func1(k=func1(k))); The func1(k) increement the value of k by 1 and return it. Here the func1(k) is called 3 times. Hence it increements value of k = 35 to 38. The result is stored in the variable k = 38.

Step 3: printf("k=%d\n", k); It prints the value of variable k "38".