Difficulty: Medium
Correct Answer: 1D63A16
Explanation:
Introduction / Context:
Binary-to-hex conversion is efficient because hexadecimal digits map neatly to groups of 4 bits (nibbles). Converting by grouping avoids long division and reduces error risk. We will pad on the left as needed to form complete 4-bit groups, then translate each nibble to a hex digit.
Given Data / Assumptions:
Concept / Approach:
Partition the binary string into 4-bit nibbles from right to left. Map each nibble to hex using 0000→0 … 1111→F. If the leftmost group has fewer than 4 bits, pad with leading zeros to a full nibble.
Step-by-Step Solution:
Verification / Alternative check:
Convert back a digit or two: D = 1101 and A = 1010 appear at the ends of the grouped string; re-grouping reproduces the original bits, confirming consistency.
Why Other Options Are Wrong:
DD63A16 duplicates the first nibble (1→D), producing too many bits.
1D33A16 replaces the middle nibble 6 with 3, altering the bit pattern.
1D63116 substitutes the last nibble A with 1, changing 1010 to 0001.
Common Pitfalls:
Grouping left-to-right instead of right-to-left, forgetting to pad the most significant nibble, or mistranslating a nibble (especially 10–15 which map to A–F). Always check the count of bits equals 4 times the number of hex digits.
Final Answer:
1D63A16
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