Binary to hexadecimal grouping — write compact hex form Express the binary number 11101011000111010 in hexadecimal notation.

Difficulty: Medium

Correct Answer: 1D63A16

Explanation:


Introduction / Context:
Binary-to-hex conversion is efficient because hexadecimal digits map neatly to groups of 4 bits (nibbles). Converting by grouping avoids long division and reduces error risk. We will pad on the left as needed to form complete 4-bit groups, then translate each nibble to a hex digit.


Given Data / Assumptions:

  • Binary input: 11101011000111010.
  • We want a hexadecimal output (base 16).
  • Left padding with zeros is allowed for a complete nibble.


Concept / Approach:

Partition the binary string into 4-bit nibbles from right to left. Map each nibble to hex using 0000→0 … 1111→F. If the leftmost group has fewer than 4 bits, pad with leading zeros to a full nibble.


Step-by-Step Solution:

Pad left to a multiple of 4 bits: 01 1101 0110 0011 1010.Map nibbles: 01→1, 1101→D, 0110→6, 0011→3, 1010→A.Combine: 1 D 6 3 A → 1D63A.Write with base tag as in options: 1D63A16.


Verification / Alternative check:

Convert back a digit or two: D = 1101 and A = 1010 appear at the ends of the grouped string; re-grouping reproduces the original bits, confirming consistency.


Why Other Options Are Wrong:

DD63A16 duplicates the first nibble (1→D), producing too many bits.

1D33A16 replaces the middle nibble 6 with 3, altering the bit pattern.

1D63116 substitutes the last nibble A with 1, changing 1010 to 0001.


Common Pitfalls:

Grouping left-to-right instead of right-to-left, forgetting to pad the most significant nibble, or mistranslating a nibble (especially 10–15 which map to A–F). Always check the count of bits equals 4 times the number of hex digits.


Final Answer:

1D63A16

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