BCD addition sanity check — one digit each Compute the sum of the two BCD digits 0011 and 0011 and report the BCD result.

Introduction / Context:
Binary-Coded Decimal (BCD) encodes each decimal digit in 4 bits. When adding BCD digits, you first add them like binary nibbles, then apply a decimal correction (adding 0110) if the raw sum exceeds 1001 (9) or generates a carry out. Here we add two BCD 3's to show a straightforward case that needs no correction.

Given Data / Assumptions:

• Digits: 0011 (3) and 0011 (3) in BCD.
• Single-digit addition (no prior carry).
• We want the resulting single BCD digit.

Concept / Approach:

Add the 4-bit nibbles as binary. If the result is ≤ 1001 (9) and no carry out of the nibble occurs, the sum is already a valid BCD digit. Only when the result > 1001 or there is a carry do we add 0110 to correct into valid BCD representation.

Step-by-Step Solution:

Verification / Alternative check:

Decimal check: 3 + 3 = 6; the BCD for 6 is 0110, confirming the result.

Why Other Options Are Wrong:

0111 equals 7, not 6.

0011 equals 3, which would imply no addition occurred.

1100 equals 12, not a valid single BCD digit without carry handling.

Common Pitfalls:

Applying the 0110 correction when it is not required, or misinterpreting BCD as pure binary of the full number. Remember: with single-digit sums ≤ 9 and no carry, the raw nibble is already correct.

Final Answer:

0110