Difficulty: Easy
Correct Answer: Staphylococcus aureus
Explanation:
Introduction / Context:
Differentiating staphylococci in the laboratory often relies on carbohydrate fermentation patterns and enzyme tests. Mannitol fermentation, especially under high salt conditions, is a classic screening step. This question targets recognition of the species most consistently able to ferment mannitol anaerobically.
Given Data / Assumptions:
Concept / Approach:
Staphylococcus aureus typically ferments mannitol, producing acid that turns indicator media yellow. This trait is useful for preliminary separation of S. aureus from coagulase-negative staphylococci such as S. epidermidis, which usually does not ferment mannitol. S. saprophyticus can be variable, but is not the canonical mannitol-fermenting staphylococcus used for routine screening.
Step-by-Step Solution:
Recall the differential principle of mannitol salt agar: salt selects for staphylococci; mannitol fermentation differentiates species.
Identify the species most consistently positive for mannitol fermentation: S. aureus.
Recognize that the test can be observed aerobically and anaerobically; fermentation indicates anaerobic acid production.
Select “Staphylococcus aureus.”
Verification / Alternative check:
Clinical algorithms combine mannitol fermentation with catalase and coagulase testing. Coagulase-positive, mannitol-fermenting isolates are highly suggestive of S. aureus.
Why Other Options Are Wrong:
Common Pitfalls:
Overreliance on a single plate reading; always confirm with coagulase and additional biochemical tests. Some atypical strains exist.
Final Answer:
Staphylococcus aureus
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