How many distinct arrangements of the letters in “FINANCE” are possible? (N appears twice; other letters are distinct.)

Difficulty: Easy

Correct Answer: 2520

Explanation:


Introduction / Context:
Again a multiset permutation: 7 letters with a duplication of N. The standard formula applies.


Given Data / Assumptions:

  • Letters: F, I, N, A, N, C, E (N × 2).


Concept / Approach:
7! / 2! counts distinct arrangements since interchanging the two N’s does not create a new word.


Step-by-Step Solution:

7! / 2! = 5040 / 2 = 2520.


Verification / Alternative check:
Check multiplicities: only N repeats; no other repeated letters.


Why Other Options Are Wrong:
5040 ignores repetition; 1260 or 840 divide by too much.


Common Pitfalls:
Misidentifying repeat counts in the word.


Final Answer:
2520

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