The percentage increased in the surface area of a cube when each side is doubled, is?

Original area = 6a 2 New area = 6(2a) 2 = 24a 2 Required increased % = (18a 2 /6a 2 ) x 100% = 300%

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Accepted Answer

Original area = 6a²
New area = 6(2a)² = 24a²
Required increased % = (18a²/6a²) x 100%
= 300%

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