If the radius of a sphere is doubled, then its surface area is increased by?

Original area = 4π r 2 , New area = 4π(2r) 2 = 16 π r 2 Required increased % = [12πr 2 ]/[4π r 2 ] x 100 %= 300%

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Accepted Answer

Original area = 4π r²,
New area = 4π(2r)² = 16 π r²
Required increased % = [12πr²]/[4π r²] x 100 %= 300%

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