If the radius of a sphere is doubled, then its volume is increased by?

Original volume = 4/3πr 3 New volume = 4/3 π (2r) 3 = 32/3 πr 3 Required increased % = [(28/3) πr 3 ] x [(3/4)πr 3 ] x 100 % = 700 %

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Accepted Answer

Original volume = 4/3πr³
New volume = 4/3 π (2r)³ = 32/3 πr³
Required increased % = [(28/3) πr³] x [(3/4)πr³] x 100 % = 700 %

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