Longest pencil in a box (space diagonal): A rectangular box has dimensions 8 cm × 6 cm × 2 cm. What is the maximum length of a pencil that can fit inside it?
Aptitude
Volume and Surface Area
Difficulty: Easy
Choose an option
-
A2 √13 cm
-
B2 √14 cm
-
C2 √26 cm
-
D10 √2 cm
Answer
Correct Answer: 2 √26 cm
Explanation
Introduction / Context:The longest object that fits inside a rectangular box equals its space diagonal. This tests 3D Pythagoras across three perpendicular edges.
Given Data / Assumptions:
- Dimensions: 8 cm, 6 cm, 2 cm
- Max length L = √(8^2 + 6^2 + 2^2)
Concept / Approach:
- Apply space diagonal formula for a cuboid.
Step-by-Step Solution:
L = √(8^2 + 6^2 + 2^2) = √(64 + 36 + 4) = √104.Since 104 = 4 * 26, L = √(4*26) = 2√26 cm.Verification / Alternative check:
Approximate: √26 ≈ 5.099 ⇒ 2√26 ≈ 10.198 cm.Why Other Options Are Wrong:
- 2√13 cm: Uses half the sum inside the root incorrectly.
- 2√14 cm: Incorrect decomposition.
- 10√2 cm: Corresponds to √(8^2 + 6^2) only, ignoring the 2 cm height.
Common Pitfalls:
- Using face diagonal instead of space diagonal.
- Arithmetic slips inside the square root.
Final Answer:
2 √26 cm