Wire length change with radius scaled: A wire is stretched so that its radius becomes one-third of the original while volume remains constant. By what factor does its length increase?

Difficulty: Easy

Correct Answer: 9 times

Explanation:


Introduction / Context:
For a wire modeled as a cylinder, volume V = π r^2 L. If radius changes but volume is fixed, length must adjust inversely with r^2. This is a pure proportionality problem.


Given Data / Assumptions:

  • Initial radius r, length L; final radius r/3; volume constant.


Concept / Approach:

  • V_initial = π r^2 L, V_final = π (r/3)^2 L_new.
  • Equate V_initial = V_final and solve for L_new / L.


Step-by-Step Solution:

π r^2 L = π (r^2 / 9) * L_new.Cancel π r^2: L = (1/9) L_new ⇒ L_new = 9 L.


Verification / Alternative check:

Area scales with r^2; decreasing radius by factor 3 decreases area by 9; length must grow by 9 to keep volume constant.


Why Other Options Are Wrong:

  • 6 times / 2 times / 1 time: Do not satisfy V constant with r → r/3.


Common Pitfalls:

  • Thinking length scales inversely with r, not r^2.
  • Forgetting cylindrical volume formula.


Final Answer:

9 times

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