Home » Aptitude » Time and Work

The ratio of efficiency of A is to C is 5:3. The ratio of number of days taken by B is to C is 2:3. A takes 6 days less than C, when A and C completes the work individually. B and C started the work and left after 2 days. The number of days taken by A to finish the remaining work is:

Correct Answer: 6

Explanation:

                       A   :   C    


 


Efficiency      5    :   3    


 


No of days   3x   :  5x     


 


Given that, 5x-6 =3x  => x = 3  


 


Number of days taken by A = 9  


 


Number of days taken by C = 15     


 


 


 


           B  :  C    


 


Days   2  :  3  


 


Therefore, Number of days taken by B = 10   


 


Work done by B and C in initial 2 days =  2 1 10 + 1 15 = 1/3  


 


Thus,  Rest work =2/3  


 


Number of days required by A to finish 2/3 work = (2/3) x 9 = 6 days


← Previous Question Next Question→

More Questions from Time and Work

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion